c++将指针地址传递给函数

Question

我想在将指针地址传递给此函数时更改函数内的数组值。当我尝试写入数组时收到运行时错误:

Exception thrown at 0x002D1D65 in interviews.exe: 0xC0000005: Access 
violation writing location 0xCCCCCCCC.

我知道我可以用不同的方式做到这一点，但这仅供我理解。

这是代码:

void func(int **p){
    *p = (int*)calloc(3, sizeof(int)); //have to stay like thiis
    *p[0] = 1;  //this line work fine but I think I assign the value 1 
                //to the address of the pointer
    *p[1] = 2;  //crashing here.
    *p[2] = 3;  
}
int main() {
    int* pm;       //have to stay like thiis
    func(&pm);     //have to stay like thiis
    int x =  pm[1];
    cout << x;
    return 0;
}

我也试过

**p[0] = 1;
**p[1] = 2;

但它也崩溃了。

我错过了什么？

Answer 1

[] 的优先级高于 *。

*p[0] = 1; 

应该是

(*p)[0] = 1; 

对其他 *p 次事件执行相同的操作。