iOS:SQLITE 插入查询错误

Question

尽管我已经重新创建列并验证了太多次，但我不断收到数据库错误 NO Column found。

表结构如下:

CREATE TABLE "ContractorTester" ("ContrTestID" VARCHAR NOT NULL ,"Ack" VARCHAR NOT NULL ,"TesterLName" VARCHAR,"TesterFName" VARCHAR,"GaugeName1" VARCHAR,"GaugeMake1" VARCHAR,"TestCrossConLic" VARCHAR,"CCLicExpDate" VARCHAR,"GaugeSerialNum1" VARCHAR,"GaugeCalibrDate1" VARCHAR,"ContrCompanyName1" VARCHAR,"ContrAddr1" VARCHAR,"ContrCity1" VARCHAR,"ContrState1" VARCHAR,"ContrZip1" VARCHAR,"ContrPhone1" VARCHAR,"Lat" DOUBLE,"Log" DOUBLE,"MCreatedDate" VARCHAR,"MUpdatedDate" VARCHAR,"ActLocalCT
" VARCHAR,"ContrTestTranID" VARCHAR PRIMARY KEY )

下面是插入查询:

INSERT OR REPLACE INTO ContractorTester ('GaugeName1','GaugeMake1','ContrPhone1','ContrTestTranID','TesterFName','ContrAddr1','ContrCity1','ContrZip1','CCLicExpDate','TestCrossConLic','GaugeCalibrDate1','Ack','TesterLName','ContrTestID','ContrState1','ContrCompanyName1','GaugeSerialNum1','ActLocalCT','Log','Lat') VALUES ('TK-99F','MIDWEST','(847) 111-3314','0','Jack','819 Main1','Lake Zurich','60051','2016-04-17T00:00:00.003','XC3673','2015-04-17T00:00:00.003','0','Skirm','5','IL','American Backflow Prevention Inc.','TG0605','1','0','0')

错误如下:

SQLiteManager: Likely SQL syntax error: INSERT OR REPLACE INTO ContractorTester ('GaugeName1','GaugeMake1','ContrPhone1','ContrTestTranID','TesterFName','ContrAddr1','ContrCity1','ContrZip1','CCLicExpDate','TestCrossConLic','GaugeCalibrDate1','Ack','TesterLName','ContrTestID','ContrState1','ContrCompanyName1','GaugeSerialNum1','ActLocalCT','Log','Lat') VALUES ('TK-99F','MIDWEST','(847) 111-3314','0','Jack','819 Main1','Lake Zurich','60051','2016-04-17T00:00:00.003','XC3673','2015-04-17T00:00:00.003','0','Skirm','5','IL','American Backflow Prevention Inc.','TG0605','1','0','0') [ table ContractorTester has no column named ActLocalCT ]
Exception Name: NS_ERROR_FAILURE
Exception Message: Component returned failure code: 0x80004005 (NS_ERROR_FAILURE) [mozIStorageConnection.createStatement]

请任何人审查并让我知道上述查询中的错误。

提前致谢。

Answer 1

替换

INSERT OR REPLACE INTO ContractorTester

与

INSERT OR REPLACE INTO ContractorTester VALUES

如果没有 VALUES，括号中的列表是要插入的列的列表，而不是要插入的值的列表。