android - 如何从 Parse.com 中删除整行并用新数据更新它

Question

删除代码

            DeleteDetails.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                final ParseObject Details = new ParseObject("Details");

                ParseUser user = ParseUser.getCurrentUser();
                Details.put("User", user);

                Details.remove("Age");
                Details.remove("Email_Address");
                Details.remove("Location");
                Details.remove("FullName");

                Details.saveInBackground();

            }
        });

我已经创建了上面的代码，它从 Parse 上的表中删除了数据，但是它会自动创建一个新字段。我希望能够输入数据，将其删除并再次输入。一旦用户退出应用程序并返回到它，数据将从云端获取并显示在 TextViews 中。

TextView 代码

ParseQuery<ParseObject> requestAge = ParseQuery.getQuery("Details");
        requestAge.getFirstInBackground(new GetCallback<ParseObject>() {

            public void done(ParseObject reqDetails, ParseException e) {
                if (reqDetails != null) {
                    Log.d("reqDetails", "Got it");
                    //Retrieve Age
                    String gettheAge = reqDetails.getString("Age");
                    EditText displayAge = (EditText)findViewById(R.id.ageET);
                    displayAge.setText(gettheAge);

                    //Retrieve E-mail address
                    String gettheEmail = reqDetails.getString("Email_Address");
                    EditText displayEmail = (EditText)findViewById(R.id.EmailET);
                    displayEmail.setText(gettheEmail);

                    //Retrieve Location:
                    String gettheLocation = reqDetails.getString("Location");
                    EditText displayLocation = (EditText)findViewById(R.id.LocationET);
                    displayLocation.setText(gettheLocation);

                    //Retrieve Name:
                    String gettheName = reqDetails.getString("FullName");
                    EditText displayName = (EditText)findViewById(R.id.NameET);
                    displayName.setText(gettheName);

                    Toast.makeText(getApplicationContext(),
                            "Successfully Recieved Personal Details",
                            Toast.LENGTH_LONG).show();

                } else {
                    Log.d("reqAge", "Empty_query");


                    Toast.makeText(getApplicationContext(),
                            "Can't Get Details, Check Connection", Toast.LENGTH_LONG)
                            .show();
                }
            }
        });

Answer 1

如果要在 Parse 中删除对象，只需对要删除的对象调用 deleteInBackground 方法即可。

Android Parse Docs