ios - 如何在 NSURL 中使用非英文字符串？

Question

当我在代码中使用日语时

func getChannelDetails(useChannelIDParam: Bool) {
    var urlString: String!
    if !useChannelIDParam {
        urlString = "https://www.googleapis.com/youtube/v3/search?part=snippet%2Cid&maxResults=50&order=viewCount&q=ポケモンGO&key=\(apikey)"
    }

我遇到了问题

fatal error: unexpectedly found nil while unwrapping an Optional value

Answer 1

日语字符(与任何国际字符一样)绝对是个问题。 URL 中允许的字符非常有限。如果它们出现在字符串中，则可失败的 URL 初始化程序将返回 nil。这些字符必须进行百分号转义。

如今，我们会使用 URLComponents 对该 URL 进行百分比编码。例如:

var components = URLComponents(string: "https://www.googleapis.com/youtube/v3/search")!
components.queryItems = [
    URLQueryItem(name: "part",       value: "snippet,id"),
    URLQueryItem(name: "maxResults", value: "50"),
    URLQueryItem(name: "order",      value: "viewCount"),
    URLQueryItem(name: "q",          value: "ポケモンGO"),
    URLQueryItem(name: "key",        value: apikey)
]
components.percentEncodedQuery = components.percentEncodedQuery?.replacingOccurrences(of: "+", with: "%2B") // you need this if your query value might have + character, because URLComponents doesn't encode this like it should
let url = components.url!

有关手动百分比编码的 Swift 2 答案，请参阅 prior revision of this answer .