php - 代码不回显 "ok"

Question

我已经搜索了很长时间，但我再次陷入困境，当我为与数据库中的密码匹配的用户输入正确的密码时，我的代码没有回显“ok”。

其他一切正常，我不确定我是否错过了任何愚蠢的事情；我可能有，所以为我的愚蠢道歉 :)

PHP:

class User {
    private $_db, $data;

    public function __construct($user = null) {
        $this->_db = DB::getInstance();
    }

    public function create($fields = array()) {
        if(!$this->_db->insert('users', $fields)) {
            throw new Exception('There was a problem registering');
        }
    }

    public function find($user = null) {
        if($user) {
            $field = (is_numeric($user)) ? 'id' : 'username';
            $data = $this->_db->get('users', array($field, '=', $user));

            if($data->count()) {
                $this->_data = $data->first();
                return true;
            }
        }
        return false;
    }

    public function login($username = null, $password = null) {
        $user = $this->find($username);

        if($user) {
            if($this->data()->password === Hash::make($password, $this->data()->salt)) {
                echo 'ok';
            }
        }

        return false;
    }

    private function data() {
        return $this->_data;
    }
}

Answer 1

在你的 login() 上，你必须像这样重写..

 public function login($username = null, $password = null) {

        $user = $this->find($username);


        if($user) {
            if($this->data()->password === Hash::make($password, $this->data()->salt)) {
                //echo 'ok';
                return true;   
            }

        }
        else { return false; }
    }

注释掉 echo 并从那里返回 true。所以你将从你的实例中调用你的函数，比如

if($someinst->find('someuser'))
      {
         echo "User Found";
      }
else { echo "Not Found"; }