gpt4 book ai didi

mysql - MySQL 中的动态交叉表查询

转载 作者:搜寻专家 更新时间:2023-10-30 23:05:14 24 4
gpt4 key购买 nike

我在使用交叉表查询从 SQL Server 切换到 MySQL 时遇到问题。

假设我有这样一张表:

| ID | BANKID | 1MONTH |        3MONTHS |        6MONTHS |       10MONTHS |       12MONTHS | 18MONTHS |       24MONTHS |       30MONTHS |       36MONTHS |
|----|--------|--------|----------------|----------------|----------------|----------------|----------|----------------|----------------|----------------|
| 1 | 1 | 3 | 2.900000095367 | 2.799999952316 | 2.700000047684 | 2.599999904633 | 2.5 | 2.400000095367 | 2.299999952316 | 2.200000047684 |
| 2 | 2 | 5 | 4.900000095367 | 4.800000190735 | 4.699999809265 | 4.599999904633 | 4.5 | 4.400000095367 | 4.300000190735 | 4.199999809265 |

我想这样显示:

BankID           1          2
1 Month 3 5
3 Months 2.9 4.9
6 Months 2.8 4.8
10 Months 2.7 4.7
12 Months 2.6 4.6
18 Months 2.5 4.5
24 Months 2.4 4.4
30 Months 2.3 4.3
36 Months 2.2 4.2

如何在 MySQL 中创建这种交叉表?

您可以在此处测试数据:http://sqlfiddle.com/#!9/9cf88/1

谢谢!

最佳答案

使用以下查询

Set @Sq = NUll;
Set @S =Null;
SET @sql = NULL;

SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(CASE WHEN id = ',
BankID,' THEN val end) AS "',
BankID,'"')

)
into @Sql
FROM
bankdeposit;


SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'select id, ''',
c.column_name,
''' as Bankid, ',
c.column_name,
' as val
from bankdeposit'
) SEPARATOR ' UNION ALL '
) into @xSq
FROM information_schema.columns c
where c.table_name = 'bankdeposit'
and c.column_name not in ('id','BankID',
'CreateDate', 'CreateBy', 'ModifyDate', 'ModifyBy',
'totalLoan','TotalDeposit','EstablishedYear','NumberOfStore')
order by c.ordinal_position;


SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'select id, ''',
c.column_name,
''' as Bankid, ',
c.column_name,
' as val
from bankdeposit'
) SEPARATOR ' UNION ALL '
) into @S
FROM information_schema.columns c
where c.table_name = 'bankdeposit'
and c.column_name in ('totalLoan','TotalDeposit',
'EstablishedYear','NumberOfStore' )
order by c.ordinal_position;


select CONCAT('select Bankid,',@sql,' from(select id, Bankid, val
from
(', @xSq,',',@S,') x order by id) xx group by Bankid
order by length(BankID),BankID');

PREPARE stmt FROM @xSq;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

Sql Fiddle Here

关于mysql - MySQL 中的动态交叉表查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27559953/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com