swift - 通过 UITapGestureRecognizer 选择器向函数发送参数参数

Question

我正在使用 TapGestureRecognizer 制作一个具有可变 View 的应用程序。当按下 View 时，我目前正在这样做

func addView(headline: String) {
    // ...
    let theHeadline = headline
    let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
    // ....
}

但是在我的函数“handleTap”中，我想像这样给它一个额外的参数(而不仅仅是发送者)

func handleTap(sender: UITapGestureRecognizer? = nil, headline: String) {
}

我如何将特定标题(每个 View 都是唯一的)作为 handleTap 函数的参数发送？

Answer 1

与其创建通用的 UITapGestureRecognizer，不如将其子类化并为标题添加一个属性:

class MyTapGestureRecognizer: UITapGestureRecognizer {
    var headline: String?
}

然后改用它:

override func viewDidLoad() {
    super.viewDidLoad()

    let gestureRecognizer = MyTapGestureRecognizer(target: self, action: "tapped:")
    gestureRecognizer.headline = "Kilroy was here."
    view1.addGestureRecognizer(gestureRecognizer)
}

func tapped(gestureRecognizer: MyTapGestureRecognizer) {
    if let headline = gestureRecognizer.headline {
        // Do fun stuff.
    }
}

我试过了。效果很好。