ios - Swift - 确定哪个按钮被按下了开关

Question

我有 4 个按钮调用一个函数。根据按下哪个按钮，我需要将按钮隐藏在按下后调用的函数中。我不知道按下了哪个按钮，所以我尝试为 4 个按钮中的每一个分配标签以通过标签识别它们并使用开关

我试过了

            switch sender.tag {
            case 1:
                self.button1.hidden = true
            case 2:
                self.button2.hidden = true
            case 3:
                self.button3.hidden = true
            case 4:
                self.button4.hidden = true

            }

但这不起作用编译器说使用未解析的标识符“发件人”

如何正确地做到这一点？

编辑:

整个函数

  if self.allowMistakeVar {

        let mistakeAlert = UIAlertController(title: "Here is title!", message: "message of alert", preferredStyle: .Alert)
        let okay = UIAlertAction(title: "OK", style: .Cancel) { UIAlertAction in

            self.allowMistakeVar = false
            self.allowMistakeButton.enabled = false


            switch sender.tag {
            case answer1Text:
                self.answer1Text.hidden = true
            case answer2Text:
                self.answer2Text.hidden = true
            case answer3Text:
                self.answer3Text.hidden = true
            case answer4Text:
                self.answer4Text.hidden = true

            }

        }

        mistakeAlert.addAction(okay)
        self.presentViewController(mistakeAlert, animated: true, completion: nil )

    } else {

另一种情况..

Answer 1

试试这个，

1) 为每个按钮分配标签

Button1.tag=1
Button2.tag=2
Button3.tag=3
Button4.tag=4

2) 然后勾选你常用的按钮 Action

func buttonClicked(sender: UIButton)
{
   switch sender.tag {
   case 1: self.sender.hidden = true //button1
           break;
   case 2: self.sender.hidden = true //button2
           break;
   case 3: self.sender.hidden = true //button3
           break;
   case 4: self.sender.hidden = true //button4
           break;
   default: ()
           break;
   }

}