constructor - Swift - 使构造函数参数上的标签可选？

Question

例如，假设您有以下代码:

struct SomeStruct {
     init (arg1: String, arg2: Int){
          // Does Stuff with Variables
     }
}

// Some Point Later

var str = "fasfsad"
var integer = 343
let smth = SomeStruct(arg1: str, arg2: integer)

是否可以修改 SomeStruct 结构以使以下代码行合法？

let smth = SomeStruct(str, integer)

Answer 1

是的，您可以通过对外部参数名称使用下划线来使参数匿名:

struct SomeStruct {
     init (_ arg1: String, _ arg2: Int){
          // Does Stuff with Variables
     }
}