typescript - 在 TS 中导出类似 "module.exports"

Question

我正在编写一个 Yeoman 生成器，当我在 JS 中这样做时:

"use strict";
var Generator = require("yeoman-generator");
var chalk = rquire("chalk");
module.exports = class extends Generator {
  initializing() {
    this.log(
      chalk.bold(
        "Welcome to the " + chalk.green("TypeScript for Serverless") + " generator!"
      )
    );
};

一切都很好。但我想我可以像这样在 TypeScript 中做到这一点:

import Base = require("yeoman-generator");
import chalk from "chalk";
type IFileConfiguration = IComplexFileConfiguration | string;

export class Generator extends Base {
  public options: IDictionary;
  public initializing() {
    this.log(
      chalk.bold(
        "Welcome to the " + chalk.green("TypeScript for Serverless") + " generator!"
      )
    );
 }

我的 tsconfig.json 是:

{
  "compilerOptions": {
    "declaration": true,
    "module": "commonjs",
    "lib": ["es2015", "es2016", "es2017", "esnext.asynciterable"],
    "target": "es2015",
    "moduleResolution": "node",
    "sourceMap": false,
    "noImplicitAny": true,
    "outDir": "./generators/app",
    "removeComments": true,
    "experimentalDecorators": false,
    "emitDecoratorMetadata": false
  },
  "include": ["src/**/*"],
  "exclude": ["node_modules", "**/*-spec.ts"]
}

但这创建了一个不同的模块定义，并且完全打破了 Yeoman 接口(interface)的期望。有没有办法让我将转译后的 JS 转换为上面列出的相同导出格式？

Answer 1

好吧，我明白了。通过在没有导出运算符的情况下定义类:

class Generator extends Base {}

然后我可以像这样在 TS 文件的末尾导出:

export = Generator

问题已解决。