typescript - 具有函数参数的对象的索引签名

Question

我需要一些关于棘手语法问题的建议。我有一个更长的所有 HTTP 方法列表，想调用适当的用户函数。

简化代码:

const httpMethods = {
  'connect': this.connect(req, res),
  'copy': this.copy(req, res),
  'delete': this.delete(req, res),
  'get': this.get(req, res),
  ...
}

let callFunction = httpMethods['get']
callFunction(req, res)

如何为对象 httpMethods 创建索引签名或类型转换 callFunction 以避免 TS 错误？

Answer 1

你可以这样转换它:

let key = "get";
let callFunction = (<any>httpMethods)[key];
callFunction(req, res);

或者像这样:

interface ISomeObject {
  connect: any;
  copy: any;
  delete: any;
  get: any;
  [key: string]: any;
}

const httpMethods: ISomeObject  = {
  'connect': this.connect(req, res),
  'copy': this.copy(req, res),
  'delete': this.delete(req, res),
  'get': this.get(req, res),
  ...
}

let key: string = "get";
let callFunction = httpMethods[key];
callFunction(req, res);

我从这个答案中改编了一个例子:https://stackoverflow.com/a/35209016/3914072

还有其他答案。