javascript - 如果在循环内部使用，则强制将 getter 结果存储在变量中

Question

考虑下课

class Smth {
  get functionWithSomeVeryUniqueName() {
    // Some heavy calculations are here
    return obj => obj; // Actually uses some vars from closure calculated above
  }
}

我想在循环内访问 getter 时出现 tslint 错误。

我。 e.以下任何行都应被视为错误:

for (var x of a) smth.functionWithSomeVeryUniqueName(x);
a.forEach(x => smth.functionWithSomeVeryUniqueName(x))
a.map(x => smth.functionWithSomeVeryUniqueName(x))
for (var q=0; q<a.length; ++q) smth.functionWithSomeVeryUniqueName(x);

以及以下任何一项 - 良好:

var functionWithSomeVeryUniqueName = smth.functionWithSomeVeryUniqueName;
for (var x of a) functionWithSomeVeryUniqueName(x);
a.forEach(x => functionWithSomeVeryUniqueName(x))
a.map(x => functionWithSomeVeryUniqueName(x))
for (var q=0; q<a.length; ++q) functionWithSomeVeryUniqueName(x);

这个也很好，因为参数只计算一次:

a.map(smth.functionWithSomeVeryUniqueName)

循环外的调用应该是有效的:

var x = smth.functionWithSomeVeryUniqueName(mySingleObject)

可以配置什么 tslint 规则来做这样的事情？

请注意，访问中的名称检查和点就足够了，我不需要确保函数属于某个具体类。

Answer 1

似乎我制定了相应的规则(demo on AstExplorer):

import * as Lint from "tslint";
import * as ts from "typescript";

const arrayMethods = new Set(["find", "findIndex", "sort", "forEach", "filter", "flatMap", "map", "every", "some", "reduce", "reduceRight"]);

export class Rule extends Lint.Rules.AbstractRule {
  public apply(sourceFile: ts.SourceFile): Lint.RuleFailure[]  {
    return this.applyWithWalker(new DisallowGetterInsideOfTheLoopWalker(sourceFile, this.getOptions()));
  }
}

class DisallowGetterInsideOfTheLoopWalker extends Lint.RuleWalker {
  private loops = 0;
  private names: Set<string>;

  constructor(sourceFile, options) {
    super(sourceFile, options);
    this.loops = 0;
    this.names = new Set(["functionWithSomeVeryUniqueName"] /* options.ruleArguments */);
  }

  public visitCallExpression(node: ts.CallExpression) {
    var isLoop = node.expression.kind === ts.SyntaxKind.PropertyAccessExpression && arrayMethods.has(node.expression.name.text);

    this.loops += isLoop as any;
    super.visitPropertyAccessExpression(node);
    this.loops -= isLoop as any;
  }

  public visitPropertyAccessExpression(node: ts.PropertyAccessExpression) {
    if (this.loops && this.names.has(node.name.text) && (this.loops > 1 || node.parent.kind === ts.SyntaxKind.CallExpression && node.parent.expression === node)) {
      this.addFailure(this.createFailure(node.name.pos, node.name.end - node.name.pos, `Do not get ${node.name.text} inside of the loop`));
    }

    super.visitPropertyAccessExpression(node);
  }

  public visitForOfStatement(node: ts.ForOfStatement) {
    this.loops += 2;
    super.visitForOfStatement(node);
    this.loops -= 2;
  }

  public visitForInStatement(node: ts.ForInStatement) {
    this.loops += 2;
    super.visitForInStatement(node);
    this.loops -= 2;
  }

  public visitForStatement(node: ts.ForStatement) {
    this.loops += 2;
    super.visitForStatement(node);
    this.loops -= 2;
  }

  public visitDoStatement(node: ts.DoStatement) {
    this.loops += 2;
    super.visitDoStatement(node);
    this.loops -= 2;
  }

  public visitWhileStatement(node: ts.WhileStatement) {
    this.loops += 2;
    super.visitWhileStatement(node);
    this.loops -= 2;
  }
}

无效案例:

for (var x of a) smth.functionWithSomeVeryUniqueName(x);
for (var x in obj) smth.functionWithSomeVeryUniqueName(x);
a.forEach(x => smth.functionWithSomeVeryUniqueName(x))
a.map(x => smth.functionWithSomeVeryUniqueName(x))
a.map(x => smth.functionWithSomeVeryUniqueName<T>(x))
for (var q=0; q<a.length; ++q) smth.functionWithSomeVeryUniqueName(x);
do smth.functionWithSomeVeryUniqueName(x); while (0)
while (1) smth.functionWithSomeVeryUniqueName(x);
while (1) (smth.functionWithSomeVeryUniqueName)(x);
while (1) var f = smth.functionWithSomeVeryUniqueName;
while (1) (smth as any).functionWithSomeVeryUniqueName;

有效案例:

var functionWithSomeVeryUniqueName = smth.functionWithSomeVeryUniqueName;

for (var x of a) functionWithSomeVeryUniqueName(x);
for (var x in obj) functionWithSomeVeryUniqueName(x);
a.forEach(x => functionWithSomeVeryUniqueName(x))
a.map(x => functionWithSomeVeryUniqueName(x))
for (var q=0; q<a.length; ++q) functionWithSomeVeryUniqueName(x);
do functionWithSomeVeryUniqueName(x); while (0)
while (1) functionWithSomeVeryUniqueName(x);
while (1) (functionWithSomeVeryUniqueName)(x);

a.map(smth.functionWithSomeVeryUniqueName)
smth.functionWithSomeVeryUniqueName(mySingleObject)

不需要的有效案例:

a.map(x => (smth.functionWithSomeVeryUniqueName)(x))