typescript - 如何强制对象将所有枚举值包含为属性键？

Question

假设我有这个枚举:

export enum translationKeys {
  resp_action_denied = "resp_action_denied",
  resp_invalid_request = "resp_invalid_request",
}

我使用此枚举从单一来源中提取唯一的字符串值。它们每个都映射到字符串解析对象:

const translations: {
  [key: string]: RequiredTranslations;
} = {
  resp_action_denied: {
    ENG: "Foo bar",
    GER: "Ich bin"
  },
  resp_invalid_request: {
    ENG: "Baz",
    GER: "Das"
  },

有没有办法强制这个对象包含所有枚举作为键，否则会抛出编译错误？

Answer 1

您可以只使用映射类型Record:

export enum translationKeys {
  resp_action_denied = "resp_action_denied",
  resp_invalid_request = "resp_invalid_request",
}

const translations: Record<translationKeys, { ENG: string, GER: string}> = {
  resp_action_denied: {
    ENG: "Foo bar",
    GER: "Ich bin"
  },
  [translationKeys.resp_invalid_request]: { // can also use computed prop to reference the enum instead of the value. 
    ENG: "Baz",
    GER: "Das"
  }
};