typescript - 如何在 typescript 中编写柯里化(Currying)函数的类型签名

Question

我如何在 typescript 中编写这样的函数的类型签名？

var apply = (fn) => (list) => 
    fn.apply(null, list);

Answer 1

给你:

var apply : (fn:Function) => (list:any[]) => any = (fn) => (list) => 
    fn.apply(null, list);

另一个例子:

var foo = (a:number) => (b:number) => (c:number) => {
    return a + b + c; 
};

var add1 = foo(1);
var add2 = foo(1)(1);

console.log(add1(1)(1)); // 3 
console.log(add2(1)); // 3