java - 如何使用 Twitter4j 检索超过 100 个结果

Question

我正在使用 Twitter4j 库检索推文，但我的目的还远远不够。目前，我从一页中获得最多 100 个。我如何在 Processing 中的以下代码中实现 maxId 和 sinceId 以便从 Twitter 搜索 API 检索超过 100 个结果？我对 Processing(和一般编程)完全陌生，所以任何关于这方面的指导都会很棒!谢谢!

void setup() {

  ConfigurationBuilder cb = new ConfigurationBuilder();
  cb.setOAuthConsumerKey("xxxx");
  cb.setOAuthConsumerSecret("xxxx");
  cb.setOAuthAccessToken("xxxx");
  cb.setOAuthAccessTokenSecret("xxxx");

  Twitter twitter = new TwitterFactory(cb.build()).getInstance();
  Query query = new Query("#peace");
  query.setCount(100);

  try {
    QueryResult result = twitter.search(query);
    ArrayList tweets = (ArrayList) result.getTweets();

    for (int i = 0; i < tweets.size(); i++) {
      Status t = (Status) tweets.get(i);

      GeoLocation loc = t.getGeoLocation();

      if (loc!=null) {
        tweets.get(i++);

        String user = t.getUser().getScreenName();
        String msg = t.getText();

        Double lat = t.getGeoLocation().getLatitude();
        Double lon = t.getGeoLocation().getLongitude();

        println("USER: " + user + " wrote: " + msg + " located at " + lat + ", " + lon);

      }
    }
  }

  catch (TwitterException te) {
    println("Couldn't connect: " + te);
  };
}

void draw() {
}

Answer 1

不幸的是你不能，至少不能以直接的方式，比如做

query.setCount(101);

作为javadoc说它最多只允许 100 条推文。

为了克服这个问题，您只需要分批请求它们，并且在每批中将您获得的最大 ID 设置为比您从上一个获得的最后一个 ID 小 1。总结一下，您将流程中的每条推文收集到一个 ArrayList 中(顺便说一句，它不应该保持通用，但其类型定义为 ArrayList<Status> - 一个包含 Status 对象的 ArrayList)，然后打印所有内容!这是一个实现:

void setup() {

  ConfigurationBuilder cb = new ConfigurationBuilder();
  cb.setOAuthConsumerKey("xxxx");
  cb.setOAuthConsumerSecret("xxxx");
  cb.setOAuthAccessToken("xxxx");
  cb.setOAuthAccessTokenSecret("xxxx");

  Twitter twitter = new TwitterFactory(cb.build()).getInstance();
  Query query = new Query("#peace");
  int numberOfTweets = 512;
  long lastID = Long.MAX_VALUE;
  ArrayList<Status> tweets = new ArrayList<Status>();
  while (tweets.size () < numberOfTweets) {
    if (numberOfTweets - tweets.size() > 100)
      query.setCount(100);
    else 
      query.setCount(numberOfTweets - tweets.size());
    try {
      QueryResult result = twitter.search(query);
      tweets.addAll(result.getTweets());
      println("Gathered " + tweets.size() + " tweets");
      for (Status t: tweets) 
        if(t.getId() < lastID) lastID = t.getId();

    }

    catch (TwitterException te) {
      println("Couldn't connect: " + te);
    }; 
    query.setMaxId(lastID-1);
  }

  for (int i = 0; i < tweets.size(); i++) {
    Status t = (Status) tweets.get(i);

    GeoLocation loc = t.getGeoLocation();

    String user = t.getUser().getScreenName();
    String msg = t.getText();
    String time = "";
    if (loc!=null) {
      Double lat = t.getGeoLocation().getLatitude();
      Double lon = t.getGeoLocation().getLongitude();
      println(i + " USER: " + user + " wrote: " + msg + " located at " + lat + ", " + lon);
    } 
    else 
      println(i + " USER: " + user + " wrote: " + msg);
  }
}

注:行

ArrayList<Status> tweets = new ArrayList<Status>();

应该是:

List<Status> tweets = new ArrayList<Status>();

因为你should always use the interface in case you want to add a different implementation .当然，如果您使用的是 Processing 2.x，那么一开始就需要这样做:

import java.util.List;