javascript - 使用 fetch()，从非 HTTP OK 状态代码中读取响应主体并捕获异常

Question

我一直在阅读 fetch() 以及如何从服务器捕获和打印可读的错误消息。理想情况下，我想在下面的示例中抛出一个总是以 Catch 2 结尾的错误，并且 console.log(`OK: ${data}`); 是如果有错误则不会运行。我可以通过直接在 response.json(); 上运行 then 来缓解 console.log(`OK: ${data}`);但我想知道实现这一目标的正确方法。

https://stackoverflow.com/a/44576265/3850405

https://developers.google.com/web/updates/2015/03/introduction-to-fetch

https://developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

C#:

[HttpGet, Route("api/specific/catalog/test")]
public async Task<IHttpActionResult> Test()
{
    return InternalServerError(new Exception("My Exception"));
}

[HttpGet, Route("api/specific/catalog/test2")]
public async Task<IHttpActionResult> Test2()
{
    return Ok("My OK Message");
}

typescript :

fetch('api/specific/catalog/test2')
    .then(response => {
        if (!response.ok) {
            response.text().then(text => {
                throw new Error(`Request rejected with status ${response.status} and message ${text}`);
            })
            .catch(error =>
                console.log(`Catch 1: ${error}`)
            );
        }
        else {
            return response.json();
        }
    })
    .then(data => {
        console.log(`OK: ${data}`);
    })
    .catch(error =>
        console.log(`Catch 2: ${error}`)
    );

确定:

异常(exception):

我想我可以做这样的事情来捕获所有错误，但它看起来很奇怪:

fetch('api/specific/catalog/test')
    .then(response => {
        if (!response.ok) {
            response.text().then(text => {
                throw new Error(`Request rejected with status ${response.status} and message ${text}`);
            })
            .catch(error =>
                console.log(`Catch: ${error}`)
            );
        }
        else {
            return response.json().then(data => {
                console.log(`OK: ${data}`);
            })
            .catch(error =>
                console.log(`Catch 2: ${error}`)
            );
        }
    })
    .catch(error =>
        console.log(`Catch 3: ${error}`)
    );

Answer 1

问题是你吞下了里面的错误，你也不需要多次捕获你只需要最后一个这样:

fetch('api/specific/catalog/test')
    .then(response => {
        if (!response.ok) {
            return response.text().then(text => {
                throw new Error(`Request rejected with status ${response.status} and message ${text}`);
            })
        }
        else {
            return response.json()
        }
    })
    .then(data => {
        console.log(`OK: ${data}`);
    })
    .catch(error =>
        console.log(`Catch 3: ${error}`)
    );