javascript - 更改方法以在 typescript 中使用 Promise.all

Question

我有以下方法:

public static zoomInMap(times: number): void {

  for (let i = 0; i < times; i++) {
    let zoomInButton = element(by.css('#main > cc-map > div.google-map-base-  container-inner > div > div.gmnoprint.gm-bundled-control.gm-bundled-control-on-bottom > div:nth-child(1) > div > div:nth-child(1)'));
    zoomInButton.click();
    browser.sleep(Config.ZOOM_ANIMATION_TIMEOUT).then(() => {
    // console.log('Map Zoomed In');
   });
 }

我想让它返回一个 Promise 。我想使用 Promise.all喜欢:

 public static zoomInMap(times: number): Promise<any> {

 return Promise.all( ? ) // ? I do not know how to do it
  for (let i = 0; i < times; i++) {
    let zoomInButton = element(by.css('#main > cc-map > div.google-map-base-container-inner > div > div.gmnoprint.gm-bundled-control.gm-bundled-control-on-bottom > div:nth-child(1) > div > div:nth-child(1)'));
    zoomInButton.click();
    browser.sleep(Config.ZOOM_ANIMATION_TIMEOUT).then(() => {
     // console.log('Map Zoomed In');
    });
  }
}

我应该如何修改代码以使用 Promise.all 。抱歉这个蹩脚的问题。

Answer 1

将您的 promise 收集到一个数组中，然后对该数组调用 Promise.all 并返回结果，即聚合的 promise :

public static zoomInMap(times: number): Promise {
  let promises = [];
  for (let i = 0; i < times; i++) {
    let zoomInButton = element(by.css('#main > cc-map > div.google-map-base-  container-inner > div > div.gmnoprint.gm-bundled-control.gm-bundled-control-on-bottom > div:nth-child(1) > div > div:nth-child(1)'));
    zoomInButton.click();
    promises.push(browser.sleep(Config.ZOOM_ANIMATION_TIMEOUT).then(() => {
        // You can do something here if you like, or remove the `then`
    }));
  }
  return Promise.all(promises);
}

我不太喜欢 TypeScript，您可能需要调整数组的声明。我已将函数的返回类型从 void 更改为 Promise。