Angular 2 -Kendo UI 网格。排序实现的问题

Question

我正在 visual studio 中使用 asp.net 开发一个 angular 2 应用程序。呈现的 HTML 使用 Kendo UI 数据网格。我正在尝试实现、滚动和排序。滚动效果很好。但是在尝试实现排序时遇到问题。我收到一个错误

错误是“一个对象文字在严格模式下不能有多个同名的属性。重复的标识符数据”。这是编译时错误

此错误涉及 loadRisks() 方法中的数据属性分配。我是 typescript 的新手，需要一些帮助。如何将 order by 子句分配给数据网格。有人可以帮忙吗。

risk-list.component.ts

import { Component, OnInit } from '@angular/core';
import { Risk } from './risk';
import { RiskService } from './risk.service';
import { GridModule, GridDataResult, PageChangeEvent, SortDescriptor, orderBy } from '@progress/kendo-angular-grid';

@Component({
    moduleId: module.id,
    selector: 'rm-risks',
    templateUrl: '/app/risk-list.component.html',
    providers: [RiskService]
})

export class RiskListComponent implements OnInit {
    private gridView: GridDataResult;
    private sort: SortDescriptor[] = [];
    private data: any[];
    private pageSize: number = 10;
    private skip: number = 0;
    title = 'Risk List';
    risks: Risk[];

    constructor(private _riskService: RiskService) {
        this.data = [];
        this.getRisks();
        this.loadRisks();
     }

    protected pageChange(event: PageChangeEvent): void {
        this.skip = event.skip;
        this.loadRisks();
    }

    protected sortChange(sort: SortDescriptor[]): void {
        this.sort = sort;
        this.loadRisks();
    }


    private loadRisks(): void {
        this.gridView = {
            data: this.data.slice(this.skip, this.skip + this.pageSize), 
            data: orderBy(this.risks, this.sort),
            total: this.data.length
        };
    }

    getRisks(): void {
        this._riskService.getRisks().then(risks => this.risks = risks);

    }

    ngOnInit(): void {
        this.getRisks();
    }
};

risk-list.component.html

<kendo-grid [data]="risks"
            [skip]="skip"
            [pageSize]="pageSize"
            [scrollable]="'virtual'"
            [rowHeight]="36"
            [height]="300"
            (pageChange)="pageChange($event)"
            [sortable]="{ mode: 'multiple' }"
            [sort]="sort"
            (sortChange)="sortChange($event)">
    <kendo-grid-column field="reference" title="Reference" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="insuredName" title="Insured Name" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="inceptionDate" title="Inception Date" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="riskType" title="Risk Type" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="status" title="Indication" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="grossPremium" title="Gross Premium" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="allocatedTo" title="Allocated To" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="allocatedCompany" title="Allocated Company" width="120">
    </kendo-grid-column>
    <kendo-grid-column field="Discontinued" width="100">
        <template kendoCellTemplate let-dataItem>
            <input type="checkbox" [checked]="dataItem.Discontinued" disabled />
        </template>
    </kendo-grid-column>
</kendo-grid>

risk.service.ts

import { Injectable } from '@angular/core';
import { Risk } from './risk';
import { Risks } from './mock-risk';
import { Http, Response } from '@angular/http';
import { Observable } from 'rxjs/Observable';
import 'rxjs/add/observable/from';


@Injectable()
export class RiskService {

    getRisks(): Promise<Risk[]> {
        return Promise.resolve(Risks);
    }

}

Answer 1

该错误意味着您不能像在 loadRisks 方法中那样拥有重复的属性。查看对象中重复的 data 属性。

private loadRisks(): void {
        this.gridView = {
            data: this.data.slice(this.skip, this.skip + this.pageSize), 
            data: orderBy(this.risks, this.sort),
            total: this.data.length
        };
    }

您应该合并这些表达式或创建一个返回所需数据值的函数。一个例子可以是:

private loadRisks(): void {
    this.gridView = {
        data: this.handleData(),
         total: this.data.length
    };
}

private handleData() {
    var pagedData = this.data.slice(this.skip, this.skip + this.pageSize)
    if (!this.sort) { return pagedData; }

    var orderedAndPagedData = orderBy(pagedData, this.sort);
    return orderedAndPagedData;
}

Plunkr:http://plnkr.co/edit/ZtaExNxX9eOQrCzYwO1N?p=preview