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java - 在 hibernate 中将多个集合映射到一个表中

转载 作者:搜寻专家 更新时间:2023-10-30 21:23:40 24 4
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我有一个 User 和一个 Log 类(我无法更改):

class User {
private long id;
private String name;
private Set<Log> accessLogs;
private Set<Log> actionLogs;
}

class Log {
private String what;
private Date when;
}

可能的映射如下所示:

<class name="com.example.User" table="users">
<id name="id" access="field">
<generator class="native" />
</id>

<property name="name" length="256" />

<set name="accessLogs" table="user_access_logs" cascade="all-delete-orphan" order-by="`when`">
<key column="user_id" />
<composite-element class="com.example.Log">
<property name="what" length="512" />
<property name="when" column="`when`" />
</composite-element>
</set>

<set name="actionLogs" table="user_action_logs" cascade="all-delete-orphan" order-by="`when`">
<key column="user_id" />
<composite-element class="com.example.Log">
<property name="what" length="512" />
<property name="when" column="`when`" />
</composite-element>
</set>

</class>

这工作正常并映射到以下数据库表:

users
+----+------+
| id | name |
+----+------+
| 1 | john |
| 2 | bill |
| 3 | nick |
+----+------+

user_access_logs
+---------+------------+---------------------+
| user_id | what | when |
+---------+------------+---------------------+
| 1 | logged in | 2010-09-21 11:25:03 |
| 1 | logged out | 2010-09-21 11:38:24 |
| 1 | logged in | 2010-09-22 10:19:39 |
| 2 | logged in | 2010-09-22 11:03:18 |
| 1 | logged out | 2010-09-22 11:48:16 |
| 2 | logged in | 2010-09-26 12:45:18 |
+---------+------------+---------------------+

user_action_logs
+---------+---------------+---------------------+
| user_id | what | when |
+---------+---------------+---------------------+
| 1 | edit profile | 2010-09-21 11:28:13 |
| 1 | post comment | 2010-09-21 11:30:40 |
| 1 | edit profile | 2010-09-21 11:31:17 |
| 1 | submit link | 2010-09-22 10:21:02 |
| 2 | submit review | 2010-09-22 11:10:22 |
| 2 | submit link | 2010-09-22 11:11:39 |
+---------+---------------+---------------------+

我的问题是在 hibernate 中如何将这 2 组(accessLogsactionLogs)映射到同一个表中,从而为日志生成以下架构:

user_logs
+---------+---------------+---------------------+--------+
| user_id | what | when | type |
+---------+---------------+---------------------+--------+
| 1 | logged in | 2010-09-21 11:25:03 | access |
| 1 | edit profile | 2010-09-21 11:28:13 | action |
| 1 | post comment | 2010-09-21 11:30:40 | action |
| 1 | edit profile | 2010-09-21 11:31:17 | action |
| 1 | logged out | 2010-09-21 11:38:24 | access |
| 1 | logged in | 2010-09-22 10:19:39 | access |
| 1 | submit link | 2010-09-22 10:21:02 | action |
| 2 | logged in | 2010-09-22 11:03:18 | access |
| 2 | submit review | 2010-09-22 11:10:22 | action |
| 2 | submit link | 2010-09-22 11:11:39 | action |
| 1 | logged out | 2010-09-22 11:48:16 | access |
| 2 | logged in | 2010-09-26 12:45:18 | access |
+---------+---------------+---------------------+--------+

编辑:我想保留 Java 代码和 Set 语义。我正在寻找鉴别器、公式或 hibernate API 扩展之类的东西,它们可以在不触及 Java 代码的情况下解决这个问题。也许是沿线的东西(虚构的 hibernate 配置如下):

<set name="accessLogs" table="user_logs" ... formula="type='access'">
<key column="user_id" />
<composite-element class="Log">
...
</composite-element>
</set>

<set name="actionLogs" table="user_logs" ... formula="type='action'">
<key column="user_id" />
<composite-element class="Log">
...
</composite-element>
</set>

Edit2:我还没有找到一个完整的解决方案。我确信可以通过扩展一些 hibernate API 来完成。

最佳答案

你试过用这种方式映射集合吗:

<set name="accessLogs" table="user_logs" where="type='access'">    

关于java - 在 hibernate 中将多个集合映射到一个表中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4107057/

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