javascript - 使用高阶函数合并相等的对象

Question

如果数组中的值彼此相等，我想“合并”对象。

这是一个例子:

"relations_entities": [
  {
    "relation": {
      "label": string,
      "inEntityId": string,
      "outEntityId": string,
      "proof": [
        {
          "text": string,
          "confidence": number,
        }
      ],
    },
    "entity": {
      "entityId": string,
      "label": string,
      "text": string,
    },
  },
  {
    "relation": {
      "label": string,
      "inEntityId": string,
      "outEntityId": string,
      "proof": [
        {
          "text": string,
          "confidence": number,
        }
      ],
    },
    "entity": {
      "entityId": string,
      "label": string,
      "text": string,
    },
  },
]

如果 relations_entities[0].relation.label 和 relations_entities[0].entity.label 等于 relations_entities[0].relation.label 和 relations_entities[0].entity.label

然后我需要这个对象是:

"relations_entities": [
  {
    "relation": {
      "label": string,
      "inEntityId": string,
      "outEntityId": string,
      "proof": [
        {
          "text": string,
          "confidence": number,
        },
        {
          "text": string,
          "confidence": number,
        }
      ],
    },
    "entity": {
      "entityId": string,
      "label": string,
      "text": string,
    },
  },
]

两个证明合并。

我尝试使用过滤器实现此行为，但我失去了理智。

也许使用 lodash 库？

有什么想法吗？

Answer 1

看看它:

let relations_entities = [
  {
    relation: {
      label: 'string',
      inEntityId: 'string',
      outEntityId: 'string',
      proof: [
        {
          text: 'string',
          confidence: 'number',
        }
      ],
    },
    entity: {
      entityId: 'string',
      label: 'string',
      text: 'string',
    },
  },
  {
    relation: {
      label: 'string',
      inEntityId: 'string',
      outEntityId: 'string',
      proof: [
        {
          text: 'string',
          confidence: 'number',
        }
      ],
    },
    entity: {
      entityId: 'string',
      label: 'string',
      text: 'string',
    },
  },
];

let merged = [];

relations_entities.forEach(el => {
  let found = false;  
  if (merged.length > 0) {
    merged.forEach(elM => {
      if (el.relation.label === elM.relation.label && !found) {
        elM.relation.proof = elM.relation.proof.concat(el.relation.proof);
        found = true;
      }
    });
  } 
  if (!found || merged.length === 0) {
    merged.push(el);
  }
});

console.log(merged);