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java - 用 Java 将整数数组写入文件的最快方法?

转载 作者:搜寻专家 更新时间:2023-10-30 20:56:11 24 4
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正如标题所说,我正在寻找将整数数组写入文件的最快方法。数组的大小会有所不同,实际上会包含 2500 到 25 000 000 个整数之间的任何值。

这是我目前使用的代码:

DataOutputStream writer = new DataOutputStream(new BufferedOutputStream(new FileOutputStream(filename)));

for (int d : data)
writer.writeInt(d);

鉴于 DataOutputStream 有一个写入字节数组的方法,我试过将 int 数组转换为字节数组,如下所示:

private static byte[] integersToBytes(int[] values) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
for (int i = 0; i < values.length; ++i) {
dos.writeInt(values[i]);
}

return baos.toByteArray();
}

像这样:

private static byte[] integersToBytes2(int[] src) {
int srcLength = src.length;
byte[] dst = new byte[srcLength << 2];

for (int i = 0; i < srcLength; i++) {
int x = src[i];
int j = i << 2;
dst[j++] = (byte) ((x >>> 0) & 0xff);
dst[j++] = (byte) ((x >>> 8) & 0xff);
dst[j++] = (byte) ((x >>> 16) & 0xff);
dst[j++] = (byte) ((x >>> 24) & 0xff);
}
return dst;
}

两者似乎都有轻微的速度提升,大约 5%。我还没有对它们进行足够严格的测试来证实这一点。

是否有任何技术可以加速此文件写入操作,或有关 Java IO 写入性能最佳实践的相关指南?

最佳答案

我看了三个选项:

  1. 使用DataOutputStream
  2. 使用 ObjectOutputStream(对于 Serializable 对象,int[] 是);和
  3. 使用 FileChannel

结果是

DataOutputStream wrote 1,000,000 ints in 3,159.716 ms
ObjectOutputStream wrote 1,000,000 ints in 295.602 ms
FileChannel wrote 1,000,000 ints in 110.094 ms

所以NIO版本是最快的。它还具有允许编辑的优势,这意味着您可以轻松更改一个整数,而 ObjectOutputStream 需要读取整个数组、修改它并将其写入文件。

代码如下:

private static final int NUM_INTS = 1000000;

interface IntWriter {
void write(int[] ints);
}

public static void main(String[] args) {
int[] ints = new int[NUM_INTS];
Random r = new Random();
for (int i=0; i<NUM_INTS; i++) {
ints[i] = r.nextInt();
}
time("DataOutputStream", new IntWriter() {
public void write(int[] ints) {
storeDO(ints);
}
}, ints);
time("ObjectOutputStream", new IntWriter() {
public void write(int[] ints) {
storeOO(ints);
}
}, ints);
time("FileChannel", new IntWriter() {
public void write(int[] ints) {
storeFC(ints);
}
}, ints);
}

private static void time(String name, IntWriter writer, int[] ints) {
long start = System.nanoTime();
writer.write(ints);
long end = System.nanoTime();
double ms = (end - start) / 1000000d;
System.out.printf("%s wrote %,d ints in %,.3f ms%n", name, ints.length, ms);
}

private static void storeOO(int[] ints) {
ObjectOutputStream out = null;
try {
out = new ObjectOutputStream(new FileOutputStream("object.out"));
out.writeObject(ints);
} catch (IOException e) {
throw new RuntimeException(e);
} finally {
safeClose(out);
}
}

private static void storeDO(int[] ints) {
DataOutputStream out = null;
try {
out = new DataOutputStream(new FileOutputStream("data.out"));
for (int anInt : ints) {
out.write(anInt);
}
} catch (IOException e) {
throw new RuntimeException(e);
} finally {
safeClose(out);
}
}

private static void storeFC(int[] ints) {
FileOutputStream out = null;
try {
out = new FileOutputStream("fc.out");
FileChannel file = out.getChannel();
ByteBuffer buf = file.map(FileChannel.MapMode.READ_WRITE, 0, 4 * ints.length);
for (int i : ints) {
buf.putInt(i);
}
file.close();
} catch (IOException e) {
throw new RuntimeException(e);
} finally {
safeClose(out);
}
}

private static void safeClose(OutputStream out) {
try {
if (out != null) {
out.close();
}
} catch (IOException e) {
// do nothing
}
}

关于java - 用 Java 将整数数组写入文件的最快方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4358875/

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