typescript - 默认函数导出类型定义

Question

我正在尝试为 pouch-redux-middleware 编写类型定义，导出单个函数:

import PouchMiddleware from 'pouch-redux-middleware'

PouchMiddleware({...})

这是我的打字定义:

interface PouchMiddleware {
  (a: any): any;
}

declare var PouchMiddleware: PouchMiddleware;

declare module "pouch-redux-middleware" {
  export = PouchMiddleware;
}

这会导致错误:

Module '"pouch-redux-middleware"' has no default export.

声明这个的正确方法是什么？

Answer 1

要转译为 commonjs 模块，您可能只需要将定义文件更改为:

declare function PouchMiddleware(a: any): any;

declare module "pouch-redux-middleware" {
    export = PouchMiddleware;
}

然后像这样导入它:

import PouchMiddleware = require("pouch-redux-middleware");

虽然有点糟透了。有人可能会提出更好的答案。

---

我相信我之前在这里的回答仅适用于针对 ES6 并将模块设置为“ES2015”:

You will need to compile with --allowSyntheticDefaultImports in order to get it to work and then change the interface in the definition file to a function:

declare function PouchMiddleware(a: any): any;

declare module "pouch-redux-middleware" {
    export = PouchMiddleware;
}

A similar thing happens with the react library. Read more here...