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database - Yesod 从数据库中获取一对多关系

转载 作者:搜寻专家 更新时间:2023-10-30 20:37:39 24 4
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我有两个表 productcategory 定义如下:

Product
category CategoryId
name Text
description Text
price Int
Category
name Text

我想从数据库中提取类型为 [(Category, [Product])] 的列表。我将如何在 Yesod 中解决这个问题?

我是全新的,我已经找了几乎一整天的时间来尝试找到一些东西来做这件事。

更新

这是我的家乡

$if null rows
<p>No products
$else
<div class="list-group menu">
$forall (category, [products]) <- rows
<div class="list-group-item">
<h4 class="list-group-item-heading">#{categoryName category}

$forall product <- products
<div class="list-group-item">
<div class="container-fluid">
<div class="col-sm-10">
<p>#{productName product} - #{productPrice product}</p>
<div class="col-md-2 text-right">
<div class="btn-group">
<a class="btn btn-default btn-xs"><div class="glyphicon glyphicon-plus"></div></a>
<a class="btn btn-default btn-xs"><div class="glyphicon glyphicon-minus"></div></a>

最佳答案

两种基本方法是:

  1. 获取所有类别的列表,然后针对每个类别,获取产品列表
  2. 使用 esqueleto 进行内部(或左)连接,然后使用 Haskell 中的排序和分组功能

第一种方法可能更简单。这是一个例子:

{-# LANGUAGE EmptyDataDecls             #-}
{-# LANGUAGE FlexibleContexts #-}
{-# LANGUAGE GADTs #-}
{-# LANGUAGE GeneralizedNewtypeDeriving #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE QuasiQuotes #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE TypeFamilies #-}
import Control.Monad.IO.Class (liftIO)
import Database.Persist
import Database.Persist.Sqlite
import Database.Persist.TH
import Data.Text (Text)
import Control.Monad (forM)

share [mkPersist sqlSettings, mkMigrate "migrateAll"] [persistLowerCase|
Product
category CategoryId
name Text
description Text
price Int
deriving Show
Category
name Text
deriving Show
|]

main :: IO ()
main = runSqlite ":memory:" $ do
runMigrationSilent migrateAll
populate
res <- query
liftIO $ print res

populate = do
watches <- insert $ Category "Watches"
insert_ $ Product watches "Rolex" "Fancy" 100
insert_ $ Product watches "Limex" "Cheap" 2

computers <- insert $ Category "Computers"
insert_ $ Product computers "MacBook Air" "Apple" 1500

query = do
cats <- selectList [] [Asc CategoryName]
forM cats $ \(Entity catId cat) -> do
products <- selectList
[ProductCategory ==. catId]
[Asc ProductName]
return (cat, map entityVal products)

关于database - Yesod 从数据库中获取一对多关系,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33357838/

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