database - laravel 4 中的外键跨数据库错误

Question

我使用外键“user_id”迁移到另一个数据库中的表“users”:当我键入 (php artisan migrate) 时，这会产生错误。

[Illuminate\Database\QueryException]
SQLSTATE[42000]: Syntax error or access violation: 1072 Key column 'user_id
' doesn't exist in table (SQL: alter table `safetyreports` add constraint s
afetyreports_user_id_foreign foreign key (`user_id`) references `users` (`i
d`) on delete cascade)

现在 laravel 创建了除 'user_id' 列之外的表。为什么 laravel 没有做专栏？

这是我的迁移代码:

Schema::create('safetyreports', function(Blueprint $table) {
            $table->increments('id');
            $table->string('afdeling');
            $table->string('contractor');
            $table->string('directe chef');
            $table->string('ploeg');
            $table->string('team');
            $table->string('plant_afd');
            $table->string('datum');
            $table->string('plaats');
            $table->string('tijd');
            $table->string('omschrijving');
            $table->foreign('user_id')
      ->references('id')->on('users')
      ->onDelete('cascade');
            $table->timestamps();
        });

This is a the important part of my Users model code: 

protected $connection = 'mysql2';
protected $table = 'users';


I have tested my Users model. It works. I perform (cross-database) user authentication with this model. 

Answer 1

在声明外键之前，必须先声明字段。

你需要先声明

Schema::create('safetyreports', function(Blueprint $table) { 
        ...
        $table->integer('user_id')->unsigned();
        ...
});

注意:unsigned 部分对此不可预测。

一旦声明了字段，您就可以像以前一样自由地声明它的关系。

希望对你有帮助... =D