gpt4 book ai didi

php - 使用 whereHas Eloquent 关系查询

转载 作者:搜寻专家 更新时间:2023-10-30 20:07:58 24 4
gpt4 key购买 nike

我有以下表格:用户

Schema::create('users', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->string('username');
$table->string('email')->unique();
$table->string('password');
$table->rememberToken();
$table->timestamps();
$table->integer('role_id')->unsigned();
$table->foreign('role_id')->references('id')->on('roles');

区域

Schema::create('areas', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->integer('location_id')->unsigned();
$table->foreign('location_id')->references('id')->on('locations')->onDelete('cascade');
$table->timestamps();

区域用户

Schema::create('area_user', function (Blueprint $table) {
$table->increments('id');
$table->integer('user_id')->unsigned();
$table->foreign('user_id')->references('id')->on('users');
$table->integer('area_id')->unsigned();
$table->foreign('area_id')->references('id')->on('areas');
});

建筑物

Schema::create('buildings', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->string('symbol')->nullable();
$table->integer('area_id')->unsigned();
$table->foreign('area_id')->references('id')->on('areas')->onDelete('cascade');
$table->integer('building_type')->unsigned();
$table->foreign('building_type')->references('id')->on('building_types');
$table->timestamps();
});

用户模型:

public function areas()
{
return $this->belongsToMany('App\Area');
}

区域模型:

public function users(){
return $this->belongsToMany('App\User');
}

建筑模型:

public function area(){
return $this->belongsTo('App\Area','area_id');
}

我如何在用户模型中编写一个查询,返回通过用户分配的区域(area_user 表)分配给用户的所有建筑物我试过了,但它返回了一个错误

Building::whereHas('area', function ($q) {
$q->whereHas('users', function ($q) {
$q->where('id', auth()->id());
});
})->get();

错误:

SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'id' in where clause is ambiguous (SQL: select * from `buildings` where exists (select * from `areas` where `buildings`.`area_id` = `areas`.`id` and exists (select * from `users` inner join `area_user` on `users`.`id` = `area_user`.`user_id` where `areas`.`id` = `area_user`.`area_id` and `id` = 11))) (View: C:\xampp\htdocs\hse\resources\views\observations\form_observation.blade.php) (View: C:\xampp\htdocs\hse\resources\views\observations\form_observation.blade.php)

最佳答案

您可以通过在 where 子句中指定表来解决歧义:

改变

$q->where('id', auth()->id());

$q->where('users.id', auth()->id());

关于php - 使用 whereHas Eloquent 关系查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46868227/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com