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mysql innoDB错误1005

转载 作者:搜寻专家 更新时间:2023-10-30 19:58:16 28 4
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我正在尝试找出导致创建表时出现错误 1005 的原因:

CREATE TABLE hospitals(
hosp_id INT NOT NULL AUTO_INCREMENT,
hosp_name VARCHAR(100) NOT NULL,
hosp_address VARCHAR(100) NOT NULL,
hosp_ph_number VARCHAR(8) NOT NULL,
PRIMARY KEY(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8;

CREATE TABLE transport(
tr_regnumber VARCHAR(8) NOT NULL,
tr_brand VARCHAR(15) NOT NULL,
tr_description VARCHAR(25),
hosp_id INT,
PRIMARY KEY (tr_regnumber),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8;

CREATE TABLE buildings(
build_id INT NOT NULL AUTO_INCREMENT,
hosp_id INT,
build_address VARCHAR(100) NOT NULL,
build_description VARCHAR(25),
PRIMARY KEY (build_id),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8;

CREATE TABLE patients(
pat_id INT NOT NULL AUTO_INCREMENT,
pat_fullname VARCHAR(150) NOT NULL,
diagnosis VARCHAR(150) NOT NULL,
emp_id INT,
pat_ph_number VARCHAR(8),
pat_address VARCHAR(100),
hosp_id INT,
pl_num INT,
PRIMARY KEY (pat_id),
FOREIGN KEY (pl_num) REFERENCES places(pl_number),
FOREIGN KEY (emp_id) REFERENCES employees(emp_id),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8;

CREATE TABLE places(
pl_number INT NOT NULL AUTO_INCREMENT,
pat_id INT NOT NULL,
hosp_id INT NOT NULL,
PRIMARY KEY (pl_number),
FOREIGN KEY (pat_id) REFERENCES patients(pat_id),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8;

CREATE TABLE employees(
emp_id INT NOT NULL AUTO_INCREMENT,
emp_fullname VARCHAR(150) NOT NULL,
emp_position VARCHAR(100) NOT NULL,
emp_ph_number VARCHAR(8),
emp_home_address VARCHAR(100),
hosp_id INT NOT NULL,
PRIMARY KEY (emp_id),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8;

这里是错误:

ERROR 1005 (HY000): Can't create table 'hospital_db.patients' (errno: 150)
ERROR 1005 (HY000): Can't create table 'hospital_db.places' (errno: 150)

这是 SHOW INNODB STATUS 的输出:

------------------------
LATEST FOREIGN KEY ERROR
------------------------
110829 11:52:01 Error in foreign key constraint of table hospital_db/places:
FOREIGN KEY (pat_id) REFERENCES patients(pat_id),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8:
Cannot resolve table name close to:
(pat_id),
FOREIGN KEY (hosp_id) REFERENCES hospitals(hosp_id)
) TYPE=InnoDB CHARACTER SET=UTF8

我使用的是 MySQL v5.1.49。

最佳答案

这似乎与您创建表的顺序和您拥有的外键依赖关系有关。

尝试在创建表之前禁用外键检查,然后像这样启用它们:

SET foreign_key_checks = 0;
-- Your create queries here
SET foreign_key_checks = 1;

干杯

关于mysql innoDB错误1005,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7228144/

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