iphone - 在同一个类中使用两个 UIPickerView

Question

我为第一个 UIPickerView 编写了这段代码

- (void)viewDidLoad
     NSURL *url = [NSURL URLWithString:
                      @"http://localhost:8080/Data/resources/converter.country/"];
        ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
        [request setDelegate:self];
        [request startAsynchronous];
      //  countrys = [[UIPickerView alloc] init];
        countrys.delegate = self;
        countrys.dataSource = self;
        countrys.showsSelectionIndicator = YES;
        countryField.inputView=countrys;


     - (NSString*)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {
        NSString *codeCity;
        codeCity=[countriesArray objectAtIndex:row];
        return codeCity;
    }

    - (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView {
        return 1;
    }

    - (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component {
        return [countriesCodeArray count];
    }

然后我想用 cities 制作另一个 UIPickerView。这是我写的

 citys.delegate = self;
    citys.dataSource = self;
    citys.showsSelectionIndicator = YES;
    cityField.inputView=citys;

但是当我点击它时，我有国家列表。我应该如何更改数据源？以及如何使用 UIPickerView 的默认功能，如 numberOfComponentsInPickerView 、 numberOfRowsInComponent: ... 和第二个 UIPickerView ？

Answer 1

您可以为您的 pickerviews 分配标签，然后可以在数据源/委托(delegate)方法中检查这些标签

citysPickerview.tag = 2

otherPickerview.tag = 1


// then you can check for these tags in pickerview datasource/delegate methods like this - 

- (NSString*)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {

        NSString *title;

      if (pickerview.tag == 1) // this is otherPickerview
      {
          title=[countriesArray objectAtIndex:row]; // your logic to get title for otherpickerview


      }
      else if (pickerview.tag == 2) // this is citysPickerview
      {
         title=[countriesArray objectAtIndex:row]; // your logic to get title for cityspickerview


      }

  return title;

}

您应该在所有数据源/委托(delegate)代码中遵循相同的机制:)