objective-c - 如何转到 UITableView 中的下一个单元格(详细信息 View )？

Question

因此，我将 UITableView 分为 3 个部分。我希望能够在第一部分(即)中打开第二行后向左滑动以转到下一个单元格，向右滑动以转到上一个单元格。

我写了滑动代码:

SecondDetailView.m

- (void)viewDidLoad
{   
    UISwipeGestureRecognizer *swipeRecognizerLeft = [[UISwipeGestureRecognizer alloc]initWithTarget:self action:@selector(swipeDetectedLeft:)];
    swipeRecognizerLeft.direction = UISwipeGestureRecognizerDirectionLeft;
    [self.view addGestureRecognizer:swipeRecognizerLeft];
    [swipeRecognizerLeft release];

    UISwipeGestureRecognizer *swipeRecognizerRight = [[UISwipeGestureRecognizer alloc]initWithTarget:self action:@selector(swipeDetectedRight:)];
    swipeRecognizerRight.direction = UISwipeGestureRecognizerDirectionRight;
    [self.view addGestureRecognizer:swipeRecognizerRight];
    [swipeRecognizerRight release];
}


- (void)swipeDetectedRight:(UIGestureRecognizer *)sender {

    NSLog(@"Right Swipe");

}

- (void)swipeDetectedLeft:(UIGestureRecognizer *)sender {
    NSLog(@"Left Swipe");
}

我该怎么做？将代码放入 Detail View 是否正确？

Answer 1

对于您的问题，我有一个非常简单的解决方案。您需要在您的 .h 文件中声明一个 NSMutableArray *arr; 并在您移动到详细信息页面时将您的数组分配给该数组。您还需要声明一个 NSString *currentPos; 变量。

- (void)swipeDetectedRight:(UIGestureRecognizer *)sender {

   currentPos--;
   NSMutableDictionary *dic=[arr objectAtIndex:currentPos];


}

- (void)swipeDetectedLeft:(UIGestureRecognizer *)sender {
     currentPos++;
     NSMutableDictionary *dic=[arr objectAtIndex:currentPos];
}

通过这种方式你可以得到数组的下一个和上一个索引值。

希望对您有所帮助。希瓦姆