c# 将 System.Reflection.FieldInfo 转换为用户定义的类型

Question

我有以下类 Point 和 Class2。我的目的是在 Class2 中检索所有 Points' 实例以将它们存储在列表中。

public class Point
    {
        int x;
        int y;
        string col;

        public Point(int abs, int ord, string clr)
        {
            this.x = abs;
            this.y = ord;
            this.col = clr;
        }

        public string toColor()
        {
            return this.col;
        }

        public int Addition()
        {
            return (this.x + this.y);
        }
    }

class Class2
    {
        int test;
        Point pt1;
        Point pt2;
        Point pt3;
        List<Point> listPt = new List<Point>() { };

        public Class2()
        {
            test = 100;
            this.pt1 = new Point(2, 3, "red");
            this.pt2 = new Point(1, 30, "blue");
            this.pt3 = new Point(5, 10, "black");
        }

        public List<Point> getAllPoint() 
        {
            foreach (var field in this.GetType().GetFields())
            {
                //retrieve current type of the anonimous type variable
                Type fieldType = field.FieldType;

                if (fieldType == typeof(Point))
                {
                    Console.WriteLine("POINT: {0}", field.ToString());
                    //listPt.Add(field); //error
                }
                else
                {
                    Console.WriteLine("Field {0} is not a Point", field.ToString());
                }
            }

            Console.ReadKey();
            return listPt;
        }
    }

但它不起作用，因为字段的类型是“System.Reflection.FieldInfo”，我该怎么做呢？看了很多文章都没有找到解决办法:

http://msdn.microsoft.com/en-us/library/ms173105.aspx

Type conversion issue when setting property through reflection

http://technico.qnownow.com/how-to-set-property-value-using-reflection-in-c/

Convert variable to type only known at run-time?

...

(我想这样做:最后一个类将有 Point 实例，具体取决于数据库，所以我不知道我将拥有多少 Point，我将需要启动一个成员函数，如 Addition。)

感谢所有想法!

Answer 1

使用FieldInfo.GetValue()方法:

listPt.Add((Point)field.GetValue(this));