python - 如果列表中的数字小于十(在 Python 中)，则在数字前面放置一个 0

Question

Write a Python program that will ask the user to enter a string of lower-case characters and then print its corresponding two-digit code. For example, if the input is "home", the output should be "08151305".

目前我正在使用我的代码列出所有号码，但我做不到让它在个位数前加一个 0。

def word ():
    output = []
    input = raw_input("please enter a string of lowercase characters: ")
    for character in input:
        number = ord(character) - 96
        output.append(number)
    print output

这是我得到的输出:

word()
please enter a string of lowercase characters: abcdefghijklmnopqrstuvwxyz
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26]

我想我可能需要将列表更改为字符串或整数才能执行此操作，但是我不确定该怎么做。

Answer 1

output.append("%02d"% number) 应该这样做。这使用 Python string formatting operations做左零填充。