c# - 使用 FileStream 在 C# 中打开文件

Question

我正在尝试打开一个我计划转换为十六进制的二进制文件，但我遇到了通过 FileStream 读取文件的问题，

private void button1_Click(object sender, EventArgs e)
{
    openFD.Title = "Insert a BIN file";
    openFD.InitialDirectory = "C:"; // Chooses the default location to open the file
    openFD.FileName = " "; // Iniitalizes the File name
    openFD.Filter = "Binary File|*.bin|Text File|*.txt"; // FIlters the types of files allowed to by chosen

    if (openFD.ShowDialog() != DialogResult.Cancel)
    {
        chosenFile = openFD.FileName;
        string directoryPath = Path.GetDirectoryName(chosenFile); // Returns the directory and the file name to reference the file
        string dirName = System.IO.Path.GetDirectoryName(openFD.FileName); // Returns the proper directory with which to refernce the file 
        richTextBox1.Text += dirName;
        richTextBox1.Text += chosenFile;
        FileStream InputBin = new FileStream(
            directoryPath, FileMode.Open, FileAccess.Read, FileShare.None);
    }
}

我收到一条错误消息，指出对路径的访问被拒绝，有什么想法吗？

现在我已经解决了这个错误，我遇到了另一个问题，我可以读取二进制文件，但我想将它显示为十六进制文件，我不确定我做错了什么，但我我没有得到 HEX 输出，它似乎是 Int 值...

if (openFD.ShowDialog() != DialogResult.Cancel)
        {

            chosenFile = openFD.FileName;
            string directoryPath = Path.GetDirectoryName(chosenFile); 
            string dirName = System.IO.Path.GetDirectoryName(openFD.FileName);
            using (FileStream stream = new FileStream(chosenFile, FileMode.Open, FileAccess.Read))
            {
                size = (int)stream.Length;
                data = new byte[size];
                stream.Read(data, 0, size);
            }

            while (printCount < size)
            {
                richTextBox1.Text += data[printCount];
                printCount++;
            }

Answer 1

您的代码有错误注释

string directoryPath = Path.GetDirectoryName(chosenFile); // Returns the directory and the file name to reference the file

不是文件名，是目录路径。你想要:

FileStream InputBin = new FileStream(chosenFile, FileMode.Open,FileAccess.Read, FileShare.None);

此外，如果我根据您的意图进行猜测，您应该将您的完整功能更新为:

private void button1_Click(object sender, EventArgs e)
{
    openFD.Title = "Insert a BIN file";
    openFD.InitialDirectory = "C:"; // Chooses the default location to open the file
    openFD.FileName = " "; // Iniitalizes the File name
    openFD.Filter = "Binary File|*.bin|Text File|*.txt"; // FIlters the types of files allowed to by chosen

    if (openFD.ShowDialog() != DialogResult.Cancel)
    {
        chosenFile = openFD.FileName;

        richTextBox1.Text += chosenFile; //You may want to replace this with = unless you mean to append something that is already there.

        FileStream InputBin = new FileStream(chosenFile, FileMode.Open,FileAccess.Read, FileShare.None);
    }
}