c# - 带有窗口的石头剪刀布游戏

Question

我正在为一项学校作业开发剪刀石头布游戏，但是当我尝试运行此脚本时，游戏无法正常运行。例如，当我单击 Rock 时，计算机只会选择相同的或选择纸张。但是玩家永远不会赢。我不知道如何解决这个问题，我已经尝试了几个小时。这是我的代码:

public partial class MainWindow : Window
{
    string Computer;
    string[] computer = { "Rock", "Paper", "Scissors" };
    Random random = new Random();
    int RandomType;
    string PlayerPicks;

    public MainWindow()
    {
        InitializeComponent();
    }

    private void StoneButton_Click(object sender, RoutedEventArgs e)
    {
        PlayerPicks = "Rock";
        RandomType = random.Next(0, 2);
        Computer = computer[RandomType];
        Game();
    }

    private void PaperButton_Click(object sender, RoutedEventArgs e)
    {
        PlayerPicks = "Paper";
        RandomType = random.Next(0, 2);
        Computer = computer[RandomType];
        Game();
    }

    private void ScissorsButton_Click(object sender, RoutedEventArgs e)
    {
        PlayerPicks = "Scissors";
        RandomType = random.Next(0, 2);
        Computer = computer[RandomType];
        Game();
    }

    void Game()
    {
        string message = "The winner is: ";
        string computerWins = "Computer!";
        string playerWins = "Player!";
        string draw = "N-Nobody?";


        if (PlayerPicks == "Rock" && Computer == "Paper") // Player: Rock, Computer: paper = computer wins
        {
            MessageBox.Show(message + computerWins);
        }
        else if (PlayerPicks == "Rock" && Computer == "Scissors") // Player: Rock, Computer: Scissors = Player wins
        {
            MessageBox.Show(message + playerWins);

        }
        else if (PlayerPicks == "Paper" && Computer == "Scissors") // Player: Paper, Computer: Scissors = Computer wins
        {
            MessageBox.Show(message + computerWins);

        }
        else if (PlayerPicks == "Paper" && Computer == "Rock") // Player: Paper, Computer: Rock = Player wins
        {
            MessageBox.Show(message + playerWins);

        }
        else if (PlayerPicks == "Scissors" && Computer == "Rock") // Player: Scissors, Computer: Rock = Computer wins
        {
            MessageBox.Show(message + computerWins);

        }
        else if (PlayerPicks == "Scissors" && Computer == "Paper") // Player: Scissors, Computer: Paper = Player wins
        {
            MessageBox.Show(message + playerWins);

        }
        if (PlayerPicks == "Scissors" && Computer == "Scissor")
        {
            MessageBox.Show(message + draw);

        }
        if (PlayerPicks == "Paper" && Computer == "Paper")
        {
            MessageBox.Show(message + draw);
        }
        if (PlayerPicks == "Rock" && Computer == "Rock")
        {
            MessageBox.Show(message + draw);
        }

Answer 1

问题 1

RandomType = random.Next(0, 2) 只生成一个介于 0 和 1 之间的数字，您需要执行 RandomType = random.Next(0, 3) 这将生成一个介于 0 和 2 之间的数字

问题2

if (PlayerPicks == "Scissors"&& Computer == "Scissor") 检查计算机是否选择了 Scissors 而不是 Scissors 只需更改这到 if (PlayerPicks == "Scissors"&& Computer == "Scissors")