python - 来自 Yelp API 的错误请求

Question

灵感来自 this Yelp tutorial ，我创建了一个脚本来搜索给定城市中的所有体育馆。我用 these updates 调整了脚本为了返回所有健身房，而不仅仅是前 20 个。您可以找到要点 here . SEARCH_LIMIT 为 20。

我遇到错误请求错误。我非常仔细地遵循了 Yelp 教程，但不确定它的来源是什么——我很确定请求已正确编码，并且我的所有 API key 都是正确的。

打印结果如下:

Traceback (most recent call last):
  File "YelpSearch.py", line 97, in <module>
    query_api()
  File "YelpSearch.py", line 74, in query_api
    response = search_yelp(offset) 
  File "YelpSearch.py", line 67, in search_yelp
    return request(API_HOST, SEARCH_PATH, url_params=url_params)
  File "YelpSearch.py", line 53, in request
    conn = urllib2.urlopen(signed_url, None)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 127, in urlopen
    return _opener.open(url, data, timeout)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 410, in open
    response = meth(req, response)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 523, in http_response
    'http', request, response, code, msg, hdrs)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 448, in error
    return self._call_chain(*args)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 531, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 400: Bad Request

Answer 1

在示例搜索参数中，他们用 + 符号替换空格:

'term': term.replace(' ', '+'),
'location': location.replace(' ', '+'),

在您的要点中，您将位置硬编码为:'New York, NY'，将空格更改为 + 应该会有所帮助。