python - 使用 R 或 Python 将数据框列中的字符串与另一个数据框列中的字符串匹配

Question

我正在尝试将数据框列中的字符串与另一个数据框列中的字符串进行匹配，并映射相应的值。两个数据框的行数不同

df1 = data.frame(name = c("(CKMB)Creatinine Kinase Muscle & Brain", "24 Hours Urine for Sodium", "Antistreptolysin O Titer", "Blood group O", lonic_code = c("27816-8-O", "27816-8-B", "1869-7", "33914-3")
df2 = data.frame(Testcomponents = c("creatinine", "blood", "potassium"))

预期输出

Test Components          lonic_code
creatinine                27816-8-O
 blood                      1869-7
potassium                    NA

Answer 1

regex_right_join 在这种情况下会很方便。

library(fuzzyjoin)
library(dplyr)

df1 %>%
  mutate(name = as.character(name)) %>%
  regex_right_join(df2 %>%
                     mutate(Testcomponents = as.character(Testcomponents)), 
                   by = c(name = "Testcomponents"), ignore_case = T) %>%
  select(Testcomponents, lonic_code)

输出是:

  Testcomponents lonic_code
1     creatinine  27816-8-O
2          blood    33914-3
3      potassium       <NA>

示例数据:

df1 <- structure(list(name = structure(1:4, .Label = c("(CKMB)Creatinine Kinase Muscle & Brain", 
"24 Hours Urine for Sodium", "Antistreptolysin O Titer", "Blood group O"
), class = "factor"), lonic_code = structure(c(3L, 2L, 1L, 4L
), .Label = c("1869-7", "27816-8-B", "27816-8-O", "33914-3"), class = "factor")), .Names = c("name", 
"lonic_code"), row.names = c(NA, -4L), class = "data.frame")

df2 <- structure(list(Testcomponents = structure(c(2L, 1L, 3L), .Label = c("blood", 
"creatinine", "potassium"), class = "factor")), .Names = "Testcomponents", row.names = c(NA, 
-3L), class = "data.frame")