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c++ - 可以将 boost 累加器用作类成员

转载 作者:太空狗 更新时间:2023-10-29 23:52:33 26 4
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我正在尝试使用 boost 累加器来计算滚动平均值。当我这样声明内联变量时:

#include <iostream>
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>

using namespace boost::accumulators;

int main()
{
// Define rolling_mean accumulator
accumulator_set<double, stats<tag::rolling_mean > > acc(tag::rolling_window::window_size = 5);
// push in some data ...
acc(1.2);
acc(2.3);
acc(3.4);
acc(4.5);

// Display the results ...
std::cout << "Mean: " << rolling_mean(acc) << std::endl;

return 0;
}

它工作得很好。当我像这样将累加器声明为类的成员时:

#include <iostream>
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>

using namespace boost::accumulators;

class DoMean {
private:
accumulator_set<double, stats<tag::rolling_mean > > m_acc(tag::rolling_window::window_size = 5);

public:

void addData(double val) {
this->m_acc(val);
}

double getMean(void) {
return rolling_mean(this->m_acc);
}
};

int main()
{
// Define an accumulator set for calculating the mean and the
// 2nd moment ...
DoMean meaner;
meaner.addData(1.2);
meaner.addData(2.3);
meaner.addData(3.4);
meaner.addData(4.5);

// push in some data ...

// Display the results ...
std::cout << "Mean: " << meaner.getMean() << std::endl;

return 0;
}

它失败了,给了编译器错误:

accumulators::tag::rolling_window::window_size is not a type
...blah blah, many type template errors etc.

最佳答案

这个问题的正确解法是这样的:

#include <iostream>
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>

using namespace boost::accumulators;

class DoMean {
private:
accumulator_set<double, stats<tag::rolling_mean > > m_acc;

public:

DoMean(void): m_acc(tag::rolling_window::window_size = 5) {}

void addData(double val) {
this->m_acc(val);
}

double getMean(void) {
return rolling_mean(this->m_acc);
}
};

int main()
{
// Define an accumulator set for calculating the mean and the
// 2nd moment ...
DoMean meaner;
meaner.addData(1.2);
meaner.addData(2.3);
meaner.addData(3.4);
meaner.addData(4.5);

// push in some data ...

// Display the results ...
std::cout << "Mean: " << meaner.getMean() << std::endl;

return 0;
}

请注意,m_acc 的初始化已从与其声明内联移动到初始化列表中。这解决了所有编译器错误。事实上,如果我们考虑这里发生的事情,最初尝试在类中使用累加器失败的原因是因为 ISO c++ 禁止内联成员初始化。

我们可以用另一个简单的类来证明这一点:

#include <iostream>

class TestInit {
public:
int m_init = 10;

};

int main() {
TestInit inits;
std::cout << "The value: " << inits.m_init << std::endl;

}

现在编译器给了我们一条有用的信息:

/home/me/prog/cpp/acctest/testinit.cxx:5:16: error: ISO C++ forbids initialization of member m_init [-fpermissive]
/home/me/prog/cpp/acctest/testinit.cxx:5:16: error: making m_init static [-fpermissive]
/home/me/prog/cpp/acctest/testinit.cxx:5:16: error: ISO C++ forbids in-class initialization of non-const static member m_init

关于c++ - 可以将 boost 累加器用作类成员,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15237135/

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