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c# - AutoMapper 映射到基于枚举的不同类型?

转载 作者:太空狗 更新时间:2023-10-29 23:47:18 25 4
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我开始实现 AutoMapper ,首先我设法将它与我已经在使用的 CaSTLe.Windsor 集成。现在我有一个 Post我想映射到 LinkPostModel 的实体或 ImagePostModel .都继承自 PostModel

1)这是我目前所拥有的:

public class PostModelFromPostEntityConverter : ITypeConverter<Post, PostModel>
{
private readonly IPostService postService;

public PostModelFromPostEntityConverter(IPostService postService)
{
if (postService == null)
{
throw new ArgumentNullException("postService");
}
this.postService = postService;
}

public PostModel Convert(ResolutionContext context)
{
Post post = (Post)context.SourceValue;
Link link = post.Link;
if (link.Type == LinkType.Html)
{
return new LinkPostModel
{
Description = link.Description,
PictureUrl = link.Picture,
PostId = post.Id,
PostSlug = postService.GetTitleSlug(post),
Timestamp = post.Created,
Title = link.Title,
UserMessage = post.UserMessage,
UserDisplayName = post.User.DisplayName
};
}
else if (link.Type == LinkType.Image)
{
return new ImagePostModel
{
PictureUrl = link.Picture,
PostId = post.Id,
PostSlug = postService.GetTitleSlug(post),
Timestamp = post.Created,
UserMessage = post.UserMessage,
UserDisplayName = post.User.DisplayName
};
}
return null;
}
}

显然是实现 AutoMapper 的重点正在删除这样的重复代码,那么在添加我的自定义规则(例如 if 子句)之前,我应该如何映射常见的东西

理想情况下,我希望它是这样的:

public class PostModelFromPostEntityConverter : ITypeConverter<Post, PostModel>
{
[...]

public PostModel Convert(ResolutionContext context)
{
Post post = (Post)context.SourceValue;
Link link = post.Link;
if (link.Type == LinkType.Html)
{
return Mapper.Map<Post, LinkPostModel>(post);
// and a few ForMember calls?
}
else if (link.Type == LinkType.Image)
{
return Mapper.Map<Post, ImagePostModel>(post);
// and a few ForMember calls?
}
return null;
}
}

2) 这个映射完成后。我有一个“父”映射,我需要在其中映射 IEnumerable<Post>以下模型:

public class PostListModel : IHasOpenGraphMetadata
{
public OpenGraphModel OpenGraph { get; set; } // og:model just describes the latest post
public IList<PostModel> Posts { get; set; }
}

所以基本上我需要另一个 TypeConverter (对吗?),这让我可以先映射帖子列表,然后创建 og:model

我有这个,但感觉有点笨拙,我觉得它可以更好:

public class PostListModelFromPostEntityEnumerableConverter : ITypeConverter<IEnumerable<Post>, PostListModel>
{
public PostListModel Convert(ResolutionContext context)
{
IEnumerable<Post> posts = (IEnumerable<Post>)context.SourceValue;
PostListModel result = new PostListModel
{
Posts = posts.Select(Mapper.Map<Post, PostModel>).ToList()
};
Post first = posts.FirstOrDefault();
result.OpenGraph = Mapper.Map<Post, OpenGraphModel>(first);
return result;
}
}

3) 我实际上还没有运行代码,所以我想到了另一个问题,那就是为什么转换器中的映射不是强类型的?

IEnumerable<Post> posts = (IEnumerable<Post>)context.SourceValue;

它可能在哪里

IEnumerable<Post> posts = context.SourceValue;

最佳答案

正在尝试获得死灵法师徽章。
如今,使用 ConstructUsing 函数可以更轻松地解决此任务,应在提供的操作中填写特定字段,但所有公共(public)字段都将转到 ForMember 执行映射。这种情况下的集合不需要任何额外的逻辑/映射配置。也具有类型集合属性的类。

cfg.CreateMap<Post, PostModel>()
.ConstructUsing(p =>
{
switch (p.Type)
{
case LinkType.Html: return new LinkPostModel
{
Title = p.Description
// other specific fields
};
case LinkType.Image: return new ImagePostModel
{
// other specific fields
};
}
return null;
})
.ForMember(x => x.PostId, m => m.MapFrom(p => p.Id));
cfg.CreateMap<PostList, PostListModel>();

关于c# - AutoMapper 映射到基于枚举的不同类型?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11818106/

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