c++ - 为什么 .* 运算符不能在 C++ 中重载？

Question

我发现这里的一些帖子讨论了运算符重载和不能在 c++ 中重载的运算符，例如 . :: .* sizeof 等。但是我找不到关于为什么要避免 .* 的确切细节或原因？你们中很少有人会认为它是重复的，但如果我能在这些链接上获得关于我想要的内容的详细信息，我会非常高兴:)

Answer 1

来自Horse's mouth :

Operator . (dot) could in principle be overloaded using the same technique as used for ->. However, doing so can lead to questions about whether an operation is meant for the object overloading . or an object referred to by . For example:

class Y {
public:
    void f();
    // ...
};

class X {   // assume that you can overload .
    Y* p;
    Y& operator.() { return *p; }
    void f();
    // ...
};

void g(X& x)
{
    x.f();  // X::f or Y::f or error?
}

This problem can be solved in several ways. At the time of standardization, it was not obvious which way would be best.

AFAIU 同样的推理适用于 .*