c++ - 如何将 unsigned int 转换为 unsigned char 数组

Question

我只需要使用按位 & 运算符提取这些字节。 0xFF 是提取一个字节的十六进制掩码。对于 2 个字节，此代码可以正常工作:

#include <stdio.h>

int main()
{
    unsigned int i = 0x7ee;
    unsigned char c[2];

    c[0] = i & 0xFF;
    c[1] = (i>>8) & 0xFF;

    printf("c[0] = %x \n", c[0]);
    printf("c[1] = %x \n", c[1]);


    return 0;
}

输出:

c[0] = ee;
c[1] = 7;

我应该怎么做才能使 4 个字节正常工作？

unsigned int i = 0x557e89f3;
unsigned char c[4];

我的代码:

unsigned char c[4];
         c[0] = i & 0xFF;
         c[1] = (i>>8) & 0xFF;
         c[2] = (i>>16) & 0xFF;
         c[3] = (i>>24) & 0xFF;
         printf("c[0] = %x \n", c[0]);
         printf("c[1] = %x \n", c[1]);
         printf("c[2] = %x \n", c[2]);
         printf("c[3] = %x \n", c[3]);

Answer 1

#include <stdio.h>

int main()
{
    unsigned int i = 0x557e89f3;
    unsigned char c[4];

    c[0] = i & 0xFF;
    c[1] = (i>>8) & 0xFF;
    c[2] = (i>>16) & 0xFF;
    c[3] = (i>>24) & 0xFF;

    printf("c[0] = %x \n", c[0]);
    printf("c[1] = %x \n", c[1]);
    printf("c[2] = %x \n", c[2]);
    printf("c[3] = %x \n", c[3]);


    return 0;
}