c++ - 防止对象过早销毁

Question

这是我的 pro::surface 类的(相关)代码:

/** Wraps up SDL_Surface* **/
class surface
{
    SDL_Surface* _surf;
public:
    /** Constructor.
     ** @param surf an SDL_Surface pointer.
     **/
    surface(SDL_Surface*);

    /** Overloaded = operator. **/
    void operator = (SDL_Surface*);

    /** calls SDL_FreeSurface(). **/
    void free();

    /** destructor. Also free()s the internal SDL_Surface. **/
    virtual ~surface();
}

现在的问题是，在我的 main 函数中，对象会自行销毁(并因此调用危险地 free()s SDL Video Surface 的析构函数!)真正的渲染开始。

int main(int argc, char** argv)
{
    ...
    // declared here
    pro::surface screen = SDL_SetVideoMode(320,240,16,SDL_HWSURFACE|SDL_DOUBLEBUF);

    // event-handling done here, but the Video Surface is already freed!
    while(!done) { ... }  // note that "screen" is not used in this loop.

    // hence, runtime error here. SDL_Quit() tries to free() the Video Surface again.
    SDL_Quit();
    return 0;
}

所以我的问题是，有什么方法可以阻止 pro::surface 实例在程序结束前自行销毁吗？手动进行内存管理是可行的:

/* this works, since I control the destruction of the object */
pro::surface* screen = new pro::surface( SDL_SetVideoMode(..) ); 

/* it destroys itself only when **I** tell it to! Muhahaha! */
delete screen;

/* ^ but this solution uses pointer (ewww! I hate pointers) */

但是没有更好的方法，不用求助于指针吗？也许有什么方法可以告诉堆栈暂时不要删除我的对象？

Answer 1

你违反了三原则，婊子。

pro::surface screen = SDL_SetVideoMode(320,240,16,SDL_HWSURFACE|SDL_DOUBLEBUF);

等于

pro::surface screen = pro::surface(SDL_SetVideoMode(320,240,16,SDL_HWSURFACE|SDL_DOUBLEBUF));

现在双倍免费，因为你违反了三原则。因此，请为您的类提供适当的复制构造函数/赋值运算符，或者禁止它们并正确地显式构造它。

编辑:这也解释了为什么您的指针版本工作正常 - 因为您没有调用拷贝。