c++ - "unsigned int *"类型的参数与 "size_t *"类型的参数不兼容

Question

我在 cuda 中使用 C++ 编写了这段代码:

// Variables
float        *query_dev;
float        *ref_dev;
float        *dist_dev;
int          *ind_dev;
cudaArray    *ref_array;
cudaError_t  result;
size_t       query_pitch;
size_t       query_pitch_in_bytes;
size_t       ref_pitch;
size_t       ref_pitch_in_bytes;
size_t       ind_pitch;
size_t       ind_pitch_in_bytes;
size_t       max_nb_query_traited;
size_t       actual_nb_query_width;
unsigned int memory_total;
unsigned int memory_free;

// Check if we can use texture memory for reference points
unsigned int use_texture = ( ref_width*size_of_float<=MAX_TEXTURE_WIDTH_IN_BYTES && height*size_of_float<=MAX_TEXTURE_HEIGHT_IN_BYTES );

// CUDA Initialisation
cuInit(0);

// Check free memory using driver API ; only (MAX_PART_OF_FREE_MEMORY_USED*100)% of   memory will be used

CUcontext cuContext;
CUdevice  cuDevice=0;
cuCtxCreate(&cuContext, 0, cuDevice);
cuMemGetInfo(&memory_free, &memory_total);

我在以下行编译时遇到错误:cuMemGetInfo(&memory_free, &memory_total);

错误是:

app.cu(311): error: argument of type "unsigned int *" is incompatible with parameter of type "size_t *"

app.cu(311): error: argument of type "unsigned int *" is incompatible with parameter of type "size_t

311 是一行:cuMemGetInfo(&memory_free, &memory_total);

我不知道这个错误是什么，你知道吗？

Answer 1

更改以下行:

unsigned int memory_total;
unsigned int memory_free;

到:

size_t memory_total;
size_t memory_free;

您可能正在尝试最初在 CUDA 3.0 之前构建的旧代码。

Source