c++ - 尝试替换字符串中的单词

Question

我试图从输出中获取单词并找到其中包含字母 Q 的任何单词。如果这个词是，则需要用“坏”一词代替。之后，我试图将每个单词附加到 output2。我在做这件事时遇到了麻烦。我编译时得到的错误是:

invalid conversion from 'const char*' to 'char' [-fpermissive]

#include <iostream>
#include <string>
#include <cstdlib>
#include <sstream>
using namespace std;
string manipulate(string x);
int main(int argc, char* argv[])
{
string input, temp, output, output2, test, test2;
int b;
cout << "Enter a string: ";
getline(cin, input);
istringstream iss(input);
while (iss >> test)
{  
      if(test.length() != 3)
      {
        test.append(" ", 1);   
        output.append(test);
      }
}

istringstream iss2(output);
while (iss2 >> test2)
{
      for(int i = 0; i<test2.length(); i++) 
   {
     switch(test2[i])
      {
           case 'q':
           test2[1]="bad";
           output2.append(test2);
           break;
      }

   }
}
cout << "Your orginal string was: " << input << endl;
cout << "Your new string is: " << output2 << endl;
cin.get();
return 0;
}

Answer 1

有更简单的方法来做到这一点:

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string s("Your homework is bad. Really bad.");

    while (s.find("bad") != string::npos)
        s.replace(s.find("bad"), 3, "good");

    cout << s << endl;

    return 0;
}

输出:

Your homework is good. Really good.

但是当指针是新值的子串时要注意大小写。在这种情况下，您可能希望移动索引以避免无限循环；示例:

string s("Your homework is good. Really good."),
       needle("good"),
       newVal("good to go");

size_t index = 0;

while ((index = s.find(needle, index)) != string::npos) {
    s.replace(index, needle.length(), newVal);
    index += newVal.length();
}

cout << s << endl;

输出

Your homework is good to go. Really good to go.