gpt4 book ai didi

c# - 代码隐藏中带有转换器的 DataTemplate

转载 作者:太空狗 更新时间:2023-10-29 23:17:44 24 4
gpt4 key购买 nike

我正在尝试在代码隐藏中加载 DataTemplate,但如果我删除 Converter,它会正常工作...但是一旦我将其放入其中,它就会崩溃。现在,我确实设置了我的状态我的命名空间并将对我的转换器的引用放在 XAML 中。例如:

<Window.Resources>
<local:StatCellConverter x:Key="myConverter" />
</Window.Resources>

这是我生成 DataTemplate 的方法:

private DataTemplate GenerateStatRowDataTemplate()
{
ParserContext pc = new ParserContext();
pc.XmlnsDictionary.Add("", "http://schemas.microsoft.com/winfx/2006/xaml/presentation");
pc.XmlnsDictionary.Add("x", "http://schemas.microsoft.com/winfx/2006/xaml");
pc.XmlnsDictionary.Add("xcdg", "http://schemas.xceed.com/wpf/xaml/datagrid");

string statRowTemplate = "<DataTemplate><xcdg:StatRow>";
statRowTemplate += "<xcdg:StatCell FieldName=\"Column4\" ResultPropertyName=\"AvgColumn4\">";
statRowTemplate += "<xcdg:StatCell.ContentTemplate>";
statRowTemplate += "<DataTemplate>";
statRowTemplate += "<TextBlock Text=\"{Binding ., Converter={StaticResource ResourceKey=myConverter}}\" />";
statRowTemplate += "</DataTemplate>";
statRowTemplate += "</xcdg:StatCell.ContentTemplate>";
statRowTemplate += "</xcdg:StatCell>";
statRowTemplate += "</xcdg:StatRow>";
statRowTemplate += "</DataTemplate>";

StringReader stringReader = new StringReader(statRowTemplate);
XmlReader xmlReader = XmlReader.Create(stringReader);
MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(statRowTemplate.ToString()));
DataTemplate dt = (DataTemplate)XamlReader.Load(ms,pc);
dt.LoadContent();
return dt;
}

我做错了什么?会不会我也必须在代码隐藏中定义我的转换器?

我的转换器

public class StatCellConverter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
Debug.WriteLine(value);

if (value.Equals("#DIV/0#"))
return "0";
return value;
}
public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}

我收到一个异常,说它无法加载 DataTemplate

最佳答案

这实际上是框架中的一个错误。通过 XmlnsDictionary 添加本地命名空间是行不通的。必须在定义了程序集和命名空间的模板定义中添加它:

如@Nerd In Training 上面的评论所述,这应该有效:

string statRowTemplate = "<DataTemplate >"; 

private DataTemplate GenerateStatRowDataTemplate()
{
ParserContext pc = new ParserContext();
pc.XmlnsDictionary.Add("", "http://schemas.microsoft.com/winfx/2006/xaml/presentation");
pc.XmlnsDictionary.Add("x", "http://schemas.microsoft.com/winfx/2006/xaml");
pc.XmlnsDictionary.Add("xcdg", "http://schemas.xceed.com/wpf/xaml/datagrid");

string statRowTemplate = "<DataTemplate xmlns:local=\"clr-namespace:MyTest;assembly=MyTest\" ><xcdg:StatRow>";
statRowTemplate += "<xcdg:StatCell FieldName=\"Column4\" ResultPropertyName=\"AvgColumn4\">";
statRowTemplate += "<xcdg:StatCell.ContentTemplate>";
statRowTemplate += "<DataTemplate>";
statRowTemplate += "<TextBlock Text=\"{Binding ., Converter={StaticResource ResourceKey=myConverter}}\" />";
statRowTemplate += "</DataTemplate>";
statRowTemplate += "</xcdg:StatCell.ContentTemplate>";
statRowTemplate += "</xcdg:StatCell>";
statRowTemplate += "</xcdg:StatRow>";
statRowTemplate += "</DataTemplate>";

StringReader stringReader = new StringReader(statRowTemplate);
XmlReader xmlReader = XmlReader.Create(stringReader);
MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(statRowTemplate.ToString()));
DataTemplate dt = (DataTemplate)XamlReader.Load(ms,pc);
dt.LoadContent();
return dt;
}

关于c# - 代码隐藏中带有转换器的 DataTemplate,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7824493/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com