c++ - 不会让我在 IF 语句后读取用户输入(作业)

Question

我在创建要导入到 csv 文件的 DVD 和软件列表的简单代码时遇到了一些问题。我的输出工作正常，但由于某种原因，我的程序跳过了我的第一部分代码。如果我去掉 IF 语句，那段代码就可以工作，所以我不明白为什么。

我的输出是这样的:

Would you like to add new media? Enter M for Movie or S for software: m Enter the name of the Movie (20 Chararters or less)Name: Enter a rating for your movie 1-5:

我的编译器 (Visual Studio 2013) 没有出现任何错误，它不允许我输入名称并直接跳到评级。任何解释或建议将不胜感激，因为我想在继续添加更多内容之前解决此问题。

这是我的代码:

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

int main(){ 
string typeM = "movie";
string typeS = "software"; 
char answer, mediainput; 
int rating = 0; 
string dir, type;
string moviename,softname; 

do
{  
  cout << "Would you like to add new media? Enter M for Movie or S for software: ";
cin >> mediainput;
cout << endl;

if (mediainput == 'm' || mediainput == 'M')  
{   
cout << "Enter the name of the Movie (20 Chararters or less) \n Name: ";
getline(cin, moviename);
cout << endl;
cout << "Enter a rating for your movie " << moviename << " 1-5 ";
cin >> rating;
if (rating < 1 || rating > 5)
 {
  cout << "You must enter a number from 1 to 5. Enter a number rating: ";
  cin >> rating;
  cout << endl;
 }

ofstream outdata("DVD_Software_inventory.csv", ios_base::app);
outdata << moviename << "," << typeM << "," << rating << "," << endl;
outdata.close();
}

if (mediainput == 's' || mediainput == 'S')
{
cout << "Enter the name of the software (20 Chararters or less) \n Software   name: " << endl;
getline(cin, softname);
cout << "Enter the directory it is in \n Directory: ";
cin >> dir;

ofstream outdata("DVD_Software_inventory.csv", ios_base::app);
outdata << softname << "," << typeS << ",," << dir << "," << endl;
outdata.close();

}
cout << "\n\nWould you like to add more? Y/N ";
cin >> answer;
cout << endl;
if (answer == 'N' || answer == 'n')
 {
  cout << "** End of Program **" << endl;
  break;
 }


} while (answer == 'Y' || answer == 'y');

system("pause");
return(0);
}

Answer 1

问题是当您的 cin >> 语句忽略“\n”(换行符)时，该字符仍在 cin 的缓冲区中。然而，getline()不会忽略“\n”字符。

因此，解决方案是明确告诉 cin 忽略“\n”字符:

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
getline(cin, moviename);

(归功于http://www.cplusplus.com/forum/beginner/24470/)