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c++ - C++中无向图算法找环的实现

转载 作者:太空狗 更新时间:2023-10-29 23:14:12 28 4
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所以基本上我想实现这个 Finding all cycles in undirected graphs在 C++ 中(唯一的区别是图表是加权的),但这不是我现在的真正问题,因为我以后可能会处理它。

我尝试将 C# 代码重写为 C++,但我对 C++ 中的 OOP 仍然没有信心,我不太明白我做错了什么。我使用了调试器,我的程序甚至没有进入 findNewCycles 函数,我也很确定还有更多问题,但目前我想知道如何开始。我的 Path 类的构造函数有问题(至少调试器提示我这个),但我不明白为什么。你能帮我么?这是我的代码:

#include <iostream>
#include <utility>
#include <vector>
#include <algorithm>

using namespace std;

class Graph {
struct Edge {
int vert[2];
double value;
public:
Edge(int vec1, int vec2, double w) {
vert[0] = vec1;
vert[1] = vec2;
value = w;
};
};

struct Path {
vector<int> vertices;
double totalValue;
public:
Path() : totalValue(0) {};
Path(vector<int> v, double tv) : vertices(v), totalValue(tv) {};
Path(const Path &a) {
totalValue = a.totalValue;
vertices = a.vertices;
}
};

int vortexCount, edgeCount, cycleCount;
vector<Path> cycles;
vector<Edge> edges;

void findNewCycles(Path a) {
int n = a.vertices[0];
int x;
Path sub(a);

for(int i = 0; i < edgeCount; i++) {
for(int j = 0; j <=1; j++) {
if (edges[i].vert[j] == n) {
x = edges[i].vert[(j+1)%2];

if (!visited(x, a)) {
sub.totalValue += edges[i].value;
sub.vertices.insert(sub.vertices.begin(), x);
findNewCycles(sub);
}
else if ((a.vertices.size() > 2) && (x == a.vertices[a.vertices.size() - 1])) {
Path normal = normalize(a);
Path inv = invert(normal);
if(isNew(normal) && isNew(inv)) cycles.push_back(normal);
}
}
}
}
}

bool equals(Path a, Path b) {
if((a.vertices.size() == b.vertices.size()) && (a.totalValue == b.totalValue)) {
for (unsigned i=0; i < a.vertices.size(); i++) {
if(a.vertices[i] != b.vertices[i]) return false;
}
return true;
}
else return false;
}

Path invert(Path a) {
Path inverted(a);
reverse(inverted.vertices.begin(), inverted.vertices.end());
return normalize(inverted);
}

Path normalize(Path a) {
Path normalized(a);
vector<int>::iterator smallest = min_element(normalized.vertices.begin(), normalized.vertices.end());
std::rotate(normalized.vertices.begin(), smallest, normalized.vertices.end());
return normalized;
}

bool isNew(Path a) {
for(int i=0; i<cycleCount; i++) {
if(equals(cycles[i], a)) {
return false;
}
}
return true;
}

bool visited(int n, Path a) {
for (unsigned i=0; i < a.vertices.size(); i++) {
if(a.vertices[i] == n) return true;
}
return false;
}

public:
Graph(int size) : vortexCount(size), edgeCount(0), cycleCount(0) {};
~Graph() {};

vector<Edge>::iterator findEdge(int v1, int v2) {
if(v1 == v2 || v1 > vortexCount || v2 > vortexCount) return edges.end();
vector<Edge>::iterator iter;

for(iter = edges.begin(); iter != edges.end(); ++iter) {
if(iter->vert[0] == v1 && iter->vert[1] == v2) return iter;
if(iter->vert[1] == v1 && iter->vert[0] == v2) return iter;
}
return edges.end();
}

bool addEdge(int v1, int v2, double value) {
if(v1 == v2 || v1 > vortexCount || v2 > vortexCount) return false;

vector<Edge>::iterator p = findEdge(v1, v2);

if(p != edges.end()) {
p->value = value;
}
else {
Edge edge(v1, v2, value);
edges.push_back(edge);
edgeCount++;
}
return true;
}

void runCycleSearch() {
for (int i = 0; i < edgeCount; i++) {
for (int j = 0; j < 2; j++) {
cout << i << " " << j;
Path searchPath;
searchPath.vertices.push_back(edges[i].vert[j]);
findNewCycles(searchPath);
}
}

for(int i=0; i<cycleCount; i++) {
for(unsigned j=0; j<cycles[i].vertices.size(); j++) {
cout << cycles[i].vertices[j] << " ";
}
cout << cycles[i].totalValue;
}
}

};

int main() {
int n, v1, v2;
double val;
bool control = true;

cin >> n;
Graph graph(n);

while(control) {
cin >> v1;
if(v1 == -1) break;
cin >> v2 >> val;

control = graph.addEdge(v1, v2, val);
}

graph.runCycleSearch();
}

最佳答案

您确定要退出 while 循环吗?

在阅读输入后尝试添加这一行:

cout << "v1=" << v1 << ", v2=" << v2 << " val=" << val << endl;

并将while (control)更改为

for (int i=0; i < n; i++)

关于c++ - C++中无向图算法找环的实现,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34938999/

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