c# - 错误 "string parameter too long"。在 microsoft.office.interop.word.find.execute

Question

我想使用 C# 创建一个 world 文档。所以这是我用于替换 word 文档变量的代码。

 private void FindAndReplace(Microsoft.Office.Interop.Word.Application WordApp, object findText, object replaceWithText) 
 {
    try {
        object matchCase = true;
        object matchWholeWord = true;
        object matchWildCards = false;
        object matchSoundsLike = false;
        object nmatchAllWordForms = false;
        object forward = true;
        object format = false;
        object matchKashida = false;
        object matchDiacritics = false;
        object matchAlefHamza = false;
        object matchControl = false;
        object read_only = false;
        object visible = true;
        object replace = 2;
        object wrap = 1;

        WordApp.Selection.Find.Execute(ref findText,
        ref matchCase, ref matchWholeWord,
        ref matchWildCards, ref matchSoundsLike,
        ref nmatchAllWordForms, ref forward,
        ref wrap, ref format, ref replaceWithText,
        ref replace, ref matchKashida,
        ref matchDiacritics, ref matchAlefHamza,
        ref matchControl);
    } catch (Exception error) {
        lblerror.Visible = true;
        lblerror.Text = error.ToString();
    }
}

但是在这里如果“replaceWithText”太孤单就会出现错误，它会说

String parameter too long.

那么如何替换长字符串呢？

Answer 1

代替使用 Find.Execute() 替换:查找文本，获取其位置，插入新文本。这不会限制您新字符串的长度。

替换特定文本的示例

// Find text 
Range range = doc.Content;
range.Find.Execute(findText);
range.Text = "new text...";

在特定文本后添加新文本的示例

// Find text 
Range range = doc.Content;
range.Find.Execute(findText);
// Define new range 
range = doc.Range(range.End + 1, range.End + 1);
range.Text = "new text...";