c# - 反序列化不同类型的JSON数组

Question

我是 JSON.NET 的新手，我需要帮助来反序列化以下 JSON

{
   "items": [
      [10, "file1", "command 1"],
      [20, "file2", "command 2"],
      [30, "file3", "command 3"]
   ]
}

为此

IList<Item> Items {get; set;}

class Item
{
   public int    Id      {get; set}
   public string File    {get; set}
   public string Command {get; set}
}

JSON 中的内容始终保持相同的顺序。

Answer 1

您可以使用自定义 JsonConverter 将 JSON 中的每个子数组转换为 Item。这是转换器所需的代码:

class ItemConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return (objectType == typeof(Item));
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        JArray array = JArray.Load(reader);
        return new Item
        {
            Id = (int)array[0],
            File = (string)array[1],
            Command = (string)array[2]
        };
    }

    public override bool CanWrite
    {
        get { return false; }
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

使用上述转换器，您可以轻松地反序列化为您的类，如下所示:

class Program
{
    static void Main(string[] args)
    {
        string json = @"
        {
           ""items"": [
              [10, ""file1"", ""command 1""],
              [20, ""file2"", ""command 2""],
              [30, ""file3"", ""command 3""]
           ]
        }";

        Foo foo = JsonConvert.DeserializeObject<Foo>(json, new ItemConverter());

        foreach (Item item in foo.Items)
        {
            Console.WriteLine("Id: " + item.Id);
            Console.WriteLine("File: " + item.File);
            Console.WriteLine("Command: " + item.Command);
            Console.WriteLine();
        }
    }
}

class Foo
{
    public List<Item> Items { get; set; }
}

class Item
{
    public int Id { get; set; }
    public string File { get; set; }
    public string Command { get; set; }
}

输出:

Id: 10
File: file1
Command: command 1

Id: 20
File: file2
Command: command 2

Id: 30
File: file3
Command: command 3

fiddle :https://dotnetfiddle.net/RXggvl