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java - 当我们使用 lombok builder 有继承关系时,如何构建一个对象?

转载 作者:太空狗 更新时间:2023-10-29 23:03:08 30 4
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在我的项目中,我使用 lombok 来避免为类编写 getter 和 setter。此外,我正在使用 lombok.Builder 构建一个对象,而不是编写 new Object() 然后设置所有值。

但是当我们有继承关系时,当我们想使用 lombok builder 构造子对象时,我得不到父字段。

例如:

@Data
@NoArgsConstructor
@AllArgsConstructor
@ToString
@EqualsAndHashCode
public class Parent{
private String nationality;
.
.
// more columns
}

子类应该是这样的:

@Data
@Builder
@NoArgsConstructor
@AllArgsConstructor
@ToString(callSuper = true)
@EqualsAndHashCode(callSuper = true)
public class Child extends Parent{
private String firstName;
private String lastName;
.
.
}

在我的测试类中,我需要构建子对象

public class Test{

public void testMethod(){
Child child = Child.builder()
.firstName("Rakesh")
.lastName("SS")
.nationality("some text")// I am not able to set nationality
.build();
}


}

请告诉我,在 lombok 中有什么方法可以处理这种情况。

最佳答案

@Builder 无法确定您希望公开哪些 Parent 字段。

@Builder 放在类上时,只有在该类上显式声明的字段才会添加到 *Builder

@Builder 放在静态方法或构造函数上时,生成的 *Builder 将为每个参数提供一个方法。

此外,如果您使用的是 @Builder,那么是否可以安全地假设至少 Child 是不可变的?

我提供了两个例子,一个是 Parent 是可变的而 Child 是不可变的,另一个是 ParentChild code> 是不可变的。

不可变父子

import static org.junit.Assert.*;
import lombok.Builder;
import lombok.EqualsAndHashCode;
import lombok.ToString;
import lombok.Value;
import lombok.experimental.NonFinal;

import org.junit.Test;

public class So32989562ValueTest {

@Value
@NonFinal
public static class Parent {

protected final String nationality;

}

@Value
@ToString(callSuper = true)
@EqualsAndHashCode(callSuper = true)
public static class Child extends Parent {

private final String firstName;

private final String lastName;

@Builder(toBuilder = true)
private Child(String nationality, String firstName, String lastName) {
super(nationality);
this.firstName = firstName;
this.lastName = lastName;
}
}

@Test
public void testChildBuilder() {

String expectedFirstName = "Jeff";
String expectedLastName = "Maxwell";
String expectedNationality = "USA";

Child result = Child.builder()
.firstName(expectedFirstName)
.lastName(expectedLastName)
.nationality(expectedNationality)
.build();

assertEquals(result.toString(), expectedFirstName, result.getFirstName());
assertEquals(result.toString(), expectedLastName, result.getLastName());
assertEquals(result.toString(), expectedNationality, result.getNationality());
}
}

可变父级,不可变子级:

import static org.junit.Assert.*;
import lombok.Builder;
import lombok.Data;
import lombok.EqualsAndHashCode;
import lombok.ToString;
import lombok.Value;

import org.junit.Test;

public class So32989562DataTest {

@Data
public static class Parent {

protected String nationality;

}

@Value
@ToString(callSuper = true)
@EqualsAndHashCode(callSuper = true)
public static class Child extends Parent {

private final String firstName;

private final String lastName;

@Builder(toBuilder = true)
private Child(String nationality, String firstName, String lastName) {
this.setNationality(nationality);
this.firstName = firstName;
this.lastName = lastName;
}
}

@Test
public void testChildBuilder() {

String expectedFirstName = "Jeff";
String expectedLastName = "Maxwell";
String expectedNationality = "USA";

Child result = Child.builder()
.firstName(expectedFirstName)
.lastName(expectedLastName)
.nationality(expectedNationality)
.build();

assertEquals(result.toString(), expectedFirstName, result.getFirstName());
assertEquals(result.toString(), expectedLastName, result.getLastName());
assertEquals(result.toString(), expectedNationality, result.getNationality());
}
}

关于java - 当我们使用 lombok builder 有继承关系时,如何构建一个对象?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32989562/

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