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c++ - 不完整类的成员函数作为 friend = 正式有效?

转载 作者:太空狗 更新时间:2023-10-29 22:59:28 24 4
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下面的代码,其中嵌套类 Info 将外部类 Impl 的两个成员函数指定为友元,用 Visual C++ 和 g++ 编译得很好,代码如下如下所示。

但是,如果成员函数没有在 Info 之前声明,那么 g++ 会提示不完整类而不是缺少声明:

In file included from ../console_io.hpp:6:0,                 from console_io.cpp:1:../console_io.impl.windows.hpp:69:47: error: invalid use of incomplete type 'class console::Display::Impl'         friend auto Impl::api_info() const -> Ref_<const Api_info>;                                               ^../console_io.impl.windows.hpp:62:20: note: definition of 'class console::Display::Impl' is not complete until the closing brace     class Display::Impl                    ^../console_io.impl.windows.hpp:70:47: error: invalid use of incomplete type 'class console::Display::Impl'

Minimal example:

struct Foo
{
class Bar
{
friend void Foo::m();
};

void m(){}
};
foo.cpp:5:28: error: invalid use of incomplete type 'struct Foo'         friend void Foo::m();                            ^foo.cpp:1:8: note: definition of 'struct Foo' is not complete until the closing brace struct Foo        ^

And so by association I wonder about the formal validity of making a member function of T a friend, at a point where T is not yet complete.


I present the actual original code that compiles, so that, if it's formally invalid, reasonable alternatives for this use case can be suggested. I think that I, as the one who's asking, am possibly the least competent to decide what's relevant or not for answers. Notation: Ref_<T> means T&.

class Display::Impl
{
private:
using Api_info = impl::winapi::Console_screen_buffer_info;

inline auto api_info() const -> Ref_<const Api_info>; // Def. after class.
inline void invalidate_api_info(); // Def. after class.

class Info
{
friend auto Impl::api_info() const -> Ref_<const Api_info>;
friend void Impl::invalidate_api_info();
private:
bool is_valid_ = false;
Api_info api_info_ = {};
};

// State:
impl::winapi::Handle text_buffer_;
mutable Info info_;

Impl( Ref_<const Impl> ) = delete;
auto operator=( Ref_<const Impl> ) -> Ref_<Impl> = delete;

public:
auto size() const
-> Point
{
auto const api_size = api_info().dwSize;
return Point{ api_size.x, api_size.y };
}

~Impl()
{} // TODO:

Impl( const Point size )
: text_buffer_( impl::winapi::CreateConsoleScreenBuffer(
impl::winapi::flag_GENERIC_READ | impl::winapi::flag_GENERIC_WRITE,
0, // No sharing
nullptr, // Default security.
impl::winapi::flag_CONSOLE_TEXTMODE_BUFFER, // The allowed value.
nullptr // Reserved.
) )
{
hopefully( text_buffer_ != impl::winapi::invalid_handle_value )
|| fail( "console::Display: CreateConsoleScreenBuffer failed" );
}
};

auto Display::Impl::api_info() const
-> Ref_<const Api_info>
{
if( not info_.is_valid_ )
{
impl::winapi::GetConsoleScreenBufferInfo( text_buffer_, &info_.api_info_ )
|| fail( "GetConsoleScreenBufferInfo failed" );
info_.is_valid_ = true;
}
return info_.api_info_;
}

void Display::Impl::invalidate_api_info()
{ info_.is_valid_ = false; }

最佳答案

经过一番挖掘,我认为这就是您要找的东西:

§9.3 [class.mfct]:

7 Previously declared member functions may be mentioned in friend declarations.

因此(据我了解标准),当您在嵌套类之前声明成员函数时,您的代码是有效的。

关于c++ - 不完整类的成员函数作为 friend = 正式有效?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36821049/

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