c# - 将对象序列化为 XML

Question

对于二进制序列化，我使用

public ClassConstructor(SerializationInfo info, StreamingContext ctxt) {

    this.cars = (OtherClass)info.GetValue("Object", typeof(OtherClass));
}
public void GetObjectData(SerializationInfo info, StreamingContext ctxt) {
    info.AddString(this.name);
    info.AddValue("Object", this.object);
}

我想为 XML 序列化做同样的事情(类实现 IXmlSerializable 接口(interface)，因为私有(private)属性 setter )，但我不知道如何将对象放入序列化程序(XmlWriter 对象)。

public void WriteXml( XmlWriter writer ) {
    writer.WriteAttributeString( "Name", Name );
    writer. ... Write object, but how ???
}
public void ReadXml( XmlReader reader ) {
    this.Name = reader.GetAttribute( "Name" );
    this.object = reader. ... how to read ??
}

可能我可以使用类似 this 的东西

XmlSerializer xsSubmit = new XmlSerializer(typeof(MyObject));
var subReq = new MyObject();
StringWriter sww = new StringWriter();
XmlWriter writer = XmlWriter.Create(sww);
xsSubmit.Serialize(writer, subReq);
var xml = sww.ToString(); // Your xml

但也许有更简单的方法只使用我从 WriteXml 方法参数获得的 XmlWriter 对象

Answer 1

下载FairlyCertain A/B Testing library .

在优秀的代码中，您会在 SerializationHelper.cs 中找到一个 XML 序列化程序类。

节选:

    /// <summary>
    /// Given a serializable object, returns an XML string representing that object.
    /// </summary>
    /// <param name="obj"></param>
    /// <returns></returns>
    public static string Serialize(object obj)
    {
        XmlSerializer xs = new XmlSerializer(obj.GetType());
        using (MemoryStream buffer = new MemoryStream())
        {
          xs.Serialize(buffer, obj);
          return ASCIIEncoding.ASCII.GetString(buffer.ToArray());
        }
    }