python - Django-Rest-Framework AssertionError HTTPresponse 预期

Question

当我使用 curl 在终端上执行以下命令时

curl -X POST http://myuser:mypassword@myweb.com:8000/call/make-call/ -d "tutor=1&billed=1"

出现以下错误

AssertionError at /call/make-call/ Expected a Response, HttpResponse or HttpStreamingResponse to be returned from the view, but received a <type 'NoneType'>

我的views.py是

@api_view(['GET', 'POST'])
def startCall(request):

    if request.method == 'POST':

        serializer = startCallSerializer(data=request.DATA)

        if serializer.is_valid():

            serializer.save()

            return Response(serializer.data, status=status.HTTP_201_CREATED)

        else:

            return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

我的serializer.py是

class startCallSerializer(serializers.ModelSerializer):

    class Meta:
        model = call
        fields = ('tutor', 'billed', 'rate', 'opentok_sessionid')

我的urls.py是

urlpatterns = patterns(
    'api.views',
    url(r'^call/make-call/$','startCall', name='startCall'),
)

Answer 1

该函数不会针对“GET”请求返回Response 对象。即if request.method == 'POST' 检查不通过。

@api_view(['GET', 'POST'])
def startCall(request):

    if request.method == 'POST':
        serializer = startCallSerializer(data=request.DATA)

        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        else:
             return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
    
    # Return Response instance if request method 
    # is not POST
    return Response({'key': 'value'}, status=status.HTTP_200_OK)